All categories

3 years ago

Help me please (˘︶˘).｡*♡

Physics

2 answers:

lisov135 [29]3 years ago

7 0

Answer:

<h3>The angle of contact does not depend upon</h3><h2><em>The inclination of surface in contact</em>.</h2>

Explanation:

Except The inclination of surface in contact, the angle of contact depends upon the temperature, soluble impurity and on cohesive force...

ss7ja [257]3 years ago

5 0

Answer:

your answer is number 4

Explanation:

Hope it helps :)

pls mark brainliets :P

You might be interested in

Paki po plss po plssssss

slega [8]

Answer:A language is a structured system of communication. Language, in a broader sense, is the method of communication that involves the use of – particularly human – languages. The scientific study of language is called linguistics

Explanation:

7 0

3 years ago

A sloping surface separating air masses that differ in temperature and moisture content is called a _________.

svet-max [94.6K]

Answer:

A sloping surface separating air masses that differ in temperature and moisture content is called a front.

5 0

4 years ago

a car accelerates at a constant rate from 15 m/s to 25 m/s while it travels a distance of 125 m. How long does it take to achiev

atroni [7]

T=Vf-Vi/s
25m/s -15m/s/ 125m
10m/s /125m
=0.08s
I hope it’s correct !

6 0

3 years ago

a stone of mass 750 kg is thrown vertically upward with a velocity of 10m/s find the potential energy at the greatest height and

Taya2010 [7]

Answer:

Potential Energy at the greatest point = 37.5 J

Explanation:

Given :

Mass is 750 g

In term of kg :

Mass is 0.75 kg .

Velocity ( v ) = 10 m / sec

We have formula for kinetic energy :

K.E. = 1 / 2 m v²

Putting values now :

K.E. = 1 / 2 × 0.75 × 10 × 10

K.E. = 1 / 2 × 75 J

K.E. = 37.5 J

Since K.E . = P.E.

Thus potential energy of stone is 37.5 J .

8 0

3 years ago

Find the values of the root mean square translational speed v, molecules in gaseous diatomic oxygen (O2), gaseous carbon dioxide

tiny-mole [99]

Answer:

For diatomic oxygen:V=539.06 m/s

For carbon dia oxide:V=459.71 m/s

For dia atomic hydrogen:V=2156.25 m/s

Explanation:

As we know that

Root mean square velocity V

$V=\sqrt{\dfrac{3RT}{M}}$

Where

R is the gas constant

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

T is the temperature (K).

M is the molecular weight.

For diatomic oxygen:

M=32 g/mol

T=273+100 = 373 K

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

$V=\sqrt{\dfrac{3RT}{M}}$

$V=\sqrt{\dfrac{3\times 8.31\times 373}{32\times 10^{-3}}}$

V=539.06 m/s

For carbon dia oxide

M=44 g/mol

T=273+100 = 373 K

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

$V=\sqrt{\dfrac{3RT}{M}}$

$V=\sqrt{\dfrac{3\times 8.31\times 373}{44\times 10^{-3}}}$

V=459.71 m/s

For dia atomic hydrogen:

M= 2 g/mol

T=273+100 = 373 K

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

$V=\sqrt{\dfrac{3RT}{M}}$

$V=\sqrt{\dfrac{3\times 8.31\times 373}{2\times 10^{-3}}}$

V=2156.25 m/s

3 0

4 years ago

Help me please (*˘︶˘*).｡*♡​

Help me please (˘︶˘).｡*♡