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Romashka-Z-Leto [24]
2 years ago
15

Help me please (*˘︶˘*).。*♡​

Physics
2 answers:
lisov135 [29]2 years ago
7 0

Answer:

<h3>The angle of contact does not depend upon</h3><h2><em>The inclination of surface in contact</em>.</h2>

Explanation:

Except The inclination of surface in contact, the angle of contact depends upon the temperature, soluble impurity and on cohesive force...

ss7ja [257]2 years ago
5 0

Answer:

your answer is number 4

Explanation:

Hope it helps :)

pls mark brainliets :P

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Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers
Vedmedyk [2.9K]
First we should convert 14.4 km into meters using the conversion factor 1km = 1000m; thus, 14.4 km = 14,400 m. Next, we should convert all minutes into seconds <span>using the conversion factor 1 min = 60 seconds; thus, 40 mins = 2400 seconds while 20 minutes = 1200 seconds. 
Speed = distance over time
Amy's speed = 14400 m / 2400 sec = 6m/s
Bill's time is 1200 sec + Amy's which is 2400 sec
Bill's speed = 14400m / 3600 sec  = 4 m/s

Therefore, Amy is faster than Bill with 2 m/s difference.</span>
3 0
3 years ago
MY NOTES A spring with a mass of 2 kg has a damping constant 14 kg/s. A force of 3.6 N is required to keep the spring stretched
il63 [147K]
Answer: What’s the question?
Explanation: everything looks good for this!! I understand now :) I think ❤️ pls give me Brainly!
7 0
3 years ago
Where does groundwater come from?
jek_recluse [69]
Groundwater is the water found underground in the cracks and spaces in soil, sand and rock. It is stored in and moves slowly through geologic formations of soil, sand and rocks called aquifers.


Hope this helps.


Please mark as brainliest..........
4 0
3 years ago
Read 2 more answers
An object whose weight is 10kg is placed on smooth plane inclined at 30° to the horizontal. find the acceleration of the object
velikii [3]

Answer:

4.9 m/s²

Explanation:

Draw a free body diagram.  There are two forces on the object:

Weight force mg pulling straight down,

and normal force N pushing perpendicular to the plane.

Sum the forces in the parallel direction.

∑F = ma

mg sin θ = ma

a = g sin θ

a = (9.8 m/s²) (sin 30°)

a = 4.9 m/s²

8 0
3 years ago
A 79.7 kg base runner begins his slide into second base while moving at a speed of 4.77 m/s. The coefficient of friction between
SashulF [63]

To solve this problem we will apply the concept related to the kinetic energy theorem. Said theorem states that the work done by the net force (sum of all forces) applied to a particle is equal to the change experienced by the kinetic energy of that particle. This is:

\Delta W = \Delta KE

\Delta W = \frac{1}{2} mv^2

Here,

m = mass

v = Velocity

Our values are given as,

m = 79.7kg

v = 4.77m/s

Replacing,

\Delta W = \frac{1}{2} (79.7kg)(4.77m/s)^2

\Delta W = 907J

Therefore the mechanical energy lost due to friction acting on the runner is 907J

6 0
3 years ago
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