1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nikitich [7]
2 years ago
11

The force required to maintain an object at a constant speed while on frictionless ice is

Physics
1 answer:
lara [203]2 years ago
3 0
If an object is on a frictionless surface, to keep it at a constant velocity you can’t apply any force because otherwise, the object will accelerate, and the velocity will change.
You might be interested in
Which of the following is most closely related to an activated complex?
Anon25 [30]

Among the choices above, the one that is most closely related to an activated complex is the transition state. The answer is letter D. This formation forms quickly and does not stay in a way compound is. It usually forms during the enzyme – substrate reaction.

5 0
3 years ago
Does the moon fall partly into earth's shadow when it is n "full"?
murzikaleks [220]
Yes, <span> the moon fall partly into earth's shadow when it is in its full size</span>
5 0
3 years ago
A ball is thrown upward with an initial velocity of +9.8 m/s. How high does it reach before it starts descending?
aksik [14]
Hope this helps you.

3 0
2 years ago
Question Part Points Submissions Used A pitcher throws a 0.200 kg ball so that its speed is 19.0 m/s and angle is 40.0° below th
postnew [5]

Answer:

The impulse is (10.88 i^ + 7.04 j^) N s

maximum force on the ball is  (4.53 10 2 i^ + 2.93 102 j ^) N  

Explanation:

In a problem of impulse and shocks we must use the impulse equation

       I = dp = pf-p₀         (1)

       p = m V

With we have vector quantities, let's decompose the velocities on the x and y axes

      V₀ = -19 m / s

      θ₀ = 40.0º  

      Vf = 46.0 m / s

      θf = 30.0º

Note that since the positive direction of the x-axis is from the batter to the pitcher, the initial velocity is negative and the angle of 40º is measured from the axis so it is in the third quadrant

      Vcx = Vo cos θ

      Voy = Vo sin θ

      Vox= -19 cos (40) = -14.6 m/s

      Voy = -19 sin (40) =  -12.2 m/s

      Vfx = 46 cos 30 = 39.8 m/s

      Vfy = 46 sin 30 =  23.0 m/s

   a) We already have all the data, substitute and calculate the impulse for each axis

      Ix = pfx -pfy

      Ix = m ( vfx -Vox)

      Ix = 0.200 ( 39.8 – (-14.6))

      Ix = 10.88 N s

      Iy = m (Vfy -Voy)

      Iy = 0.200 ( 23.0- (-12.2))

      Iy=  7.04 N s

In vector form it remains

       I =  (10.88 i^ + 7.04 j^) N s

   b) As we have the value of the impulse in each axis we can use the expression that relates the impulse to the average force and your application time, so we must calculate the average force in each interval.

         I = Fpro Δt

In the first interval

        Fpro = (Fm + Fo) / 2

With the Fpro the average value of the force, Fm the maximum value and Fo the minimum value, which in this case is zero

         Fpro = (Fm +0) / 2

In the second interval the force is constant

          Fpro = Fm

In the third interval

         Fpro = (0 + Fm) / 2

Let's replace and calculate

         I =  Fpro1 t1 +Fpro2 t2  +Fpro3 t3

         I = Fm/2 4 10⁻³ + Fm 20 10⁻³+ Fm/2 4 10⁻³  

         I = Fm  24 10⁻³ N s

         Fm = I / 24 10⁻³

         Fm = (10.88 i^ + 7.04 j^) / 24 10⁻³

         Fm = (4.53 10² i^ + 2.93 10² j ^) N

maximum force on the ball is  (4.53 10 2 i^ + 2.93 102 j ^) N  

3 0
3 years ago
A person on a rocket traveling at 0.47 c (with respect to the Earth) observes a meteor come from behind and pass her at a speed
zhannawk [14.2K]

The concept to solve this problem is related to the relativistic physics for which the speed of the object in different frames of reference is related. This concept is called Velocity-addition formula

and can be written as,

u = \frac{v+u'}{1+\frac{vu'}{c^2}}

Where,

u = Velocity of a body within a Lorentz Frame

v = Velocity of a second frame

u'= The transformed velocity of the body within the second frame

c = speed of light

Replacing we have to

u = \frac{v+u'}{1+\frac{vu'}{c^2}}

u = \frac{0.47c+0.47c}{1+\frac{0.47c*0.47c}{c^2}}

u = 0.769c

u \approx 230'700.000m/s

Therefore the meteor moving with respect to the Earth to 230'700.000m/s

7 0
2 years ago
Other questions:
  • A school's new pump can fill the swimming pool in 2 hours, and the old pump takes 5 hours. What is the time required in hours to
    15·1 answer
  • The acceleration of gravity on Earth is approximately 10 m/s2 (more precisely, 9.8 m/s2). If you drop a rock from a tall buildin
    15·1 answer
  • An electrical motor spins at a constant 1975.0 rpm. If the armature radius is 7.112 cm, what is the acceleration of the edge of
    14·1 answer
  • I am trying to find the magnitude of a resultant vector. Do i take inconsideration the negatives when i find the x &amp; y compo
    6·1 answer
  • Determine which law is appropriate for solving the following problem.
    8·2 answers
  • A disk has 128 tracks of 32 sectors each, on each surface of eight platters. The disk spins at 3600 RPM and takes 15 ms to move
    9·1 answer
  • You push a cart with mass 30 kg forward, giving it an acceleration of 5 m/s2How much force did you apply? O A. 0.17 N O B. 35 N
    10·1 answer
  • Which of the following is true of work?
    5·1 answer
  • There are many uses for permanent magnets and temporary magnets like an electromagnet. Electric appliances with electric motors
    13·1 answer
  • Which would most likely form a homogenous mixture?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!