Question

How much force is required to produce a torque of 100 Nm if the force is applied at an angle of 40 at a distance of 25 cm from the pivot?

Answer 1

Answer:

Force, F = 622.28 N

Explanation:

It is given that,

Torque, $\tau=100\ N-m$

Angle between force and displacement, $\theta=40^{\circ}$

Distance, d = 25 cm = 0.25 m

We need to find the force required to produce the torque. Torque produced by an object is given by :

$\tau=Fd\sin\theta$

F is force required to produce torque

$F=\dfrac{\tau}{d\sin\theta}\\\\F=\dfrac{100}{0.25\times \sin(40)}\\\\F=622.28\ N$

So, applied force is 622.28 N.