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3 years ago

Two ways that radio waves are used for transmitting information. Help me please.

Physics

1 answer:

Travka [436]3 years ago

3 0

1. Stop transmitting start and stop sending photons. This is typical morse code like transmissions of information. By varying the pattern of starts stops you vary the information sent. Also used in digital communications over radios, modems, and pulse dialing over radio/phones.

<span>2. Change the frequency. You use a pattern of shorter and longer wavelengths of radio waves higher and lower energies of individual photons to transmit information. This is frequency modulation </span>

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Which statement best describes the equation CaCO3 + 2HCl → CaCl2 + CO2 + H2O? CaCO3 is a reactant; it is present before the reac

Marat540 [252]

Answer:

CaCl2 is a reactant

Explanation:

Calcium carbonate (CaCO3) is a reagent, it is found on the left side, what is found on the right side are the products.

6 0

3 years ago

Read 2 more answers

According to coulombs law, what will happen to the force between two charged particles if the magnitude are increased by 6 times

seropon [69]

Answer: The electrostatic force will be the same

Explanation:

According to Coulomb's Law, when two electrically charged bodies come closer, appears a force that attracts or repels them, depending on the sign of the charges of this two bodies or particles.

In this sense, this law states the following:

"The electrostatic force $F_{E}$ between two point charges $q_{1}$ and $q_{2}$ is proportional to the product of the charges and inversely proportional to the square of the distance $d$ that separates them, and has the direction of the line that joins them"

$F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}$ (1)

Being $K$ is a proportionality constant.

Now, if each $q_{1}$ and $q_{2}$ are increased by 6, and the distance between them as well, we will have the following:

$F_{E}= K\frac{6 q_{1}. 6 q_{2}}{(6d)^{2}}$ (2)

$F_{E}= 36 K\frac{q_{1}. q_{2}}{36d^{2}}$ (3)

Simplifying:

$F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}$ (4)

Comparing (1) with (4) we can see the electrostatic force is the same.

4 0

4 years ago

A 25 kg circular disk has a diameter of 2.5 feet and a thickness of 2.5 cm. Find the density of the disk in kg/m3. Next, find th

Gre4nikov [31]

Answer:

Assume that $\rm g= 9.81\; N\cdot kg^{-1}$ ; $\rho(\text{Water}) = \rm 1000\;kg\cdot m^{-3}$ .

Density of the disk: approximately $\rm 2.19\times 10^{3}\; kg\cdot m^{-3}$ .

Weight of the disk: approximately $\rm 245\;N$ .

Buoyant force on the disk if it is submerged under water: approximately $\rm 112\; N$ .

The disk will sink when placed in water.

Explanation:

Convert the dimensions of this disk to SI units:

Diameter: $d = \rm 25\; inches = (25\times 0.3048)\; m = 0.762\;m$ .
Thickness $h = \rm 2.5\; cm = (2.5\times 0.01)\; m = 0.025\;m$ .

The radius of a circle is 1/2 its diameter:

$\displaystyle r = \rm \frac{1}{2}\times 0.762\;m = 0.381\; m$ .

Volume of this disk:

$V(\text{disk}) = \pi\cdot r^{2}\cdot h = \pi\times 0.381^{2}\times 0.025 \approx 0.0114009\; m^{3}$ .

Density of this disk:

$\displaystyle \rho(\text{disk}) = \frac{m}{V} = \rm \frac{25\; kg}{0.0114009\; m^{3}} = 2.19\times 10^{3}\;kg\cdot m^{-3}$ .

$\rho(\text{disk}) >\rho(\text{water})$ indicates that the disk will sink when placed in water.

Weight of the object:

$W(\text{disk}) = m\cdot g = \rm 25\times 9.81 = 245.25\; N$ .

The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately $\rm 0.0114009\; m^{3}$ of water. The buoyant force on the disk will be:

$\begin{aligned}F(\text{buoyant force}) &= W(\text{Water Displaced}) \\& = \rho\cdot V(\text{Water Displaced})\cdot g\\ & = \rm 1\times 10^{3}\; kg\cdot m^{-3}\times 0.0114009\; m^{3}\times 9.81\; N\cdot kg^{-1}\\ &\approx \rm 112\; N\end{aligned}$ .

The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.

3 0

3 years ago

There is no( ) in time between the action and the reaction

Lesechka [4]

There is no (gap) in time between the action and the reaction

hope that helps:)

4 0

4 years ago

A 0.0208 m diameter coin rolls up a 18.0◦ inclined plane. The coin starts with an initial angular speed of 56.0 rad/s and rolls

anastassius [24]

Answer:

h = 0.0259 m

Explanation: