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erica [24]
3 years ago
11

Steam at 200 °C is cooled to 105°c. What happens to the volume? Mass? Average kinetic energyy of the molecules and the particle

movement?
Chemistry
1 answer:
taurus [48]3 years ago
8 0
The mass stays the same because if you have the same amount of steam then it can't change. The volume will get slightly smaller because the average kinetic energy of the molecules is less, so they move around less, so they take up less space. The particles are moving less fast. 
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Which salt is produced when sulfuric acid and calcium hydroxide react completely?
AnnyKZ [126]

Answer: Option (4) is the correct answer.

Explanation:

When sulfuric acid reacts with calcium hydroxide then it results in the formation of calcium sulfate and water.

The chemical reaction for the same will be as follows.

     H_{2}SO_{4} + Ca(OH)_{2} \rightarrow CaSO_{4} + 2H_{2}O

Thus, we can conclude that CaSO_{4} salt is produced when sulfuric acid and calcium hydroxide react completely.

3 0
3 years ago
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Determine which is the control group and which is the experimental group in the following scenario ( Scientists are testing a ne
Daniel [21]

Answer:

The group given the sugar pills.

Explanation:

The control group is the ones given sugar pills because they did not get the experimental aspirin

3 0
2 years ago
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Write the chemical equation for the reaction that occurs when 6 m hcl solution is added to the reaction mixture.
Semenov [28]
When u add the solution to the chemical's
6 0
3 years ago
What is the standard enthalpy of a reaction for which the equilibrium constant is (a) doubled, (b) halved when the temperature i
Alexxandr [17]

Answer:

a) 48KJ

b) -48KJ

Explanation:

Given that;

ln(K2/K1) = ΔH°/R(1/T2 - 1/T1)

K2= equilibrium constant at T2

K1 = equilibrum constant at T1

R = gas constant

T1 = initial temperature

T2 = final temperature

When we double the equilibrium constant K1; K2 = 2K1

T1 = 310 K

T2 = 310 + 15 = 325 K

ln(2K1/K1) =- ΔH°/R(1/T2 - 1/T1)

ln2 = -ΔH°/8.314(1/325 - 1/310)

0.693 = -ΔH°/8.314(3.08 * 10^-3 - 3.2 * 10^-3)

0.693 = -ΔH°/8.314 (-0.00012)

0.693 = 0.00012ΔH°/8.314

0.693 * 8.314 = 0.00012ΔH°

ΔH° = 0.693 * 8.314/0.00012

ΔH° = 48KJ

b) K2 =K1/2

ln(K1/2/K1) =- ΔH°/R(1/T2 - 1/T1)

ln (1/2) = -ΔH°/8.314 (1/325 - 1/310)

-0.693 = -ΔH°/8.314  (-0.00012)

-0.693 = 0.00012ΔH°/8.314

-0.693 * 8.314 = 0.00012ΔH°

ΔH°= -0.693 * 8.314/0.00012

ΔH°= -48KJ

6 0
3 years ago
Benzene can be nitrated with a mixture of nitric and sulfuric acids. How do we do that?
Montano1993 [528]

Answer:

We can do the nitration of benzene by treating the benzene with a mixture of nitric acid and sulphuric acid by not extending the temperature of 50°C

Explanation:

Nitration of benzene takes place by treating the benzene with a mixture of nitric acid and sulphuric acid at low temperatures such as the temperatures below 50°C

The nitration of benzene takes place through electrophilic substitution reaction

In this reaction the electrophile is nitronium ion (NO2+) which performs an electrophilic substitution reaction on the benzene ring and during the reaction an intermediate will also be formed in which there will be positive charge distributed in the benzene

These electrophile is generated when nitric acid is treated with sulphuric acid

As nitric acid is a strong oxidising agent, here in this case the oxidation state of nitrogen will change from +5 to +3

The reactions regarding the nitration of benzene is present in the file attached

5 0
3 years ago
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