The balanced equation is attached in the image below. The coefficients are 2, 2, blank.
Answer:
5.71 g
Explanation:
Step 1: Write the balanced equation
2 K + Cl₂ ⇒ 2 KCl
Step 2: Calculate the moles corresponding to 12.0 g of KCl
The molar mass of KCl is 74.55 g/mol.
12.0 g × 1 mol/74.55 g = 0.161 mol
Step 3: Calculate the moles of Cl₂ needed to produce 0.161 moles of KCl
The molar ratio of Cl₂ to KCl is 1:2. The moles of Cl₂ needed are 1/2 × 0.161 mol = 0.0805 mol
Step 4: Calculate the mass corresponding to 0.0805 moles of Cl₂
The molar mass of Cl₂ is 70.91 g/mol.
0.0805 mol × 70.91 g/mol = 5.71 g
Answer:

Explanation:
Percent yield is the ratio of the amount actually produced to how much could theoretically be produced. It is found using this formula:

For this reaction, the theoretical or expected yield is 325.0 grams. The actual yield is 123.8 grams.

Divide.


Round to the nearest hundredth. The 9 in the hundredth place tells us to round the 0 to a 1 .

The percent yield is about <u>38.1%</u>