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3 years ago

How do you detemine the charge of an element based on jts valence electrons

1 answer:

8 0

Look at the protons and electrons and rememeber metals want to get rid of electrons to be perfect. Nonmetals are wanting to take in. Metals are negatives in electrons. Opposite for nonmetals.

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Which of the following would be a clue that a rock is igneous?

ryzh [129]

Answer:

Explanation:

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2 years ago

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If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under th

AlladinOne [14]

At STP, the volume of a gas represents the number of particles.That said, from the chemical reaction one mole of oxygen reacts with two moles of co to produce the product, CO2At STP, 3 moles of Oxygen will produce 6 moles of CO2. Hence It follows that at standard temperature and pressure, 6.0 L of CO2 will be produced. Option D.

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2 years ago

A small file or organization use a payroll program for calculating staff wages each month each employee has a unique payroll num

Rama09 [41]

Answer:

the company is now aarav and its CEO of samruddhi and is the CEO in meeting with holika and will come in to help with holika as brainlyiest as the company's chief financial adviser to solve di problems

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it was the most common thing that happened in my first pregnancy in my first year and I m and the other girl Bo.. were pretty good vibes for the last day of samruddhi but they are still very much a many years after I was knowing that

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2 years ago

A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %

kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

$H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)$

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and $y_{C-6}$ and $y_{N_2}$ are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

$H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol$

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

$Q=-40036+(-672.21)=-40708.21J$

Finally we convert this result to kJ:

$Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ$

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1 year ago

How does coffee keep you awake?

ivanzaharov [21]

Coffee keeps you awake due to the caffeine in it. Caffeine is considered a psychoactive drug which energizes people by releasing a chemical in the body.

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2 years ago

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