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notka56 [123]
2 years ago
12

From the list below, which name appears in two different parts of the body? *

Physics
1 answer:
Kisachek [45]2 years ago
7 0

Answer:

Ngjfibfubbb

Explanation:

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A ball is thrown straight down with a speed of Va2.00 from a building 40.00 meters high. How much S time passes before the ball
-Dominant- [34]

Answer:

Option C is the correct answer.

Explanation:

Considering vertical motion of ball:-

Initial velocity, u =  2 m/s

Acceleration , a = 9.81 m/s²

Displacement, s = 40 m

We have equation of motion s= ut + 0.5 at²

Substituting

   s= ut + 0.5 at²

    40 = 2 x t + 0.5 x 9.81 x t²

   4.9t²  + 2t - 40 = 0

   t = 2.66 s   or t = -3.06 s

So, time is 2.66 s.

Option C is the correct answer.

6 0
3 years ago
Each ball has a negligible size and a mass of 11.5 kg and is attached to the end of a rod whose mass may be neglected. The rod i
Digiron [165]

Answer:

3.31m/s

Explanation:

Angular momentum for 3s is

L = L_i_n_i + L_3_s

L = 2(11.5kg) + \int\limits^ {3s}_ {0s} {(t^2 + 2)} \, dt

L = 23kg+(\frac{t^3}{3} +2t)^ {3s}_ {0s}\\\\L=38kgm/s

Moment if inertia is

I = 2ml^2

I = 2(11.5)(0.5)^2\\\\I=5.75kgm^2

Angular speed

ω = L/I

= 38 / 5.75\\\\=6.61

The speed of each ball is

V = ωL

= 6.61\times0.5\\\\= 3.31m/s

7 0
2 years ago
Your friend turns the volume up on their speaker system, so that the sound intensity is 4 times greater than it was beforehand.
erica [24]

Answer:

4

Explanation:

We know that intensity I = P/A where P = power and A = area through which the power passes through.

Now, let the initial intensity of the speaker be I₀ and its initial power be P₀. Since the intensity is increased by a factor of 4, the new intensity be I and new power be P.

So, I = P/A and I₀ = P₀/A

Now, if I = 4I₀,

P/A = 4P₀/A

P = 4P₀

Now, energy E = Pt, where t = time. So, P = E/t and P₀ = E₀/t

Substituting P and P₀ into the equation, we have

P = 4P₀

E/t = 4E₀/t

E = 4E₀

Since the energy is four times the initial energy, the energy output increases by a factor of 4.

4 0
3 years ago
A certain circuit is composed of two series resistors. The total resistance is 10 Ohms. One of the resistors is 4 Ohms. The othe
Mariulka [41]
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

  • A certain circuit is composed of two series resistors
  • The total resistance is 10 ohms
  • One of the resistor is 4 ohms

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • We have to find the value of other resistor?

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

We know that,

In series combination,

  • When a number of resistances are connected in series, the equivalent I.e resultant resistance is equal to the sum of the individual resistances and is greater than any individual resistance

<u>That </u><u>is</u><u>, </u>

Rn in series = R1 + R2 + R3.....So on

<u>Therefore</u><u>, </u>

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

We have,

R1 + R2 = 10 Ω

4 + R2 = 10Ω

R2 = 10 - 4

R2 = 6Ω

Hence, The value of R2 resistor in series is 6Ω

4 0
1 year ago
About how many times greater is the density of a neutron star compared to a white dwarf?
irina1246 [14]

Answer:

Explanation:

over a million times

7 0
2 years ago
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