A monobromination reaction of an alkane involves an alkane and bromine. The position of the hydrogen atom that will be substituted by the bromine free radical will depend on the order of the alkane. The bromine will attach to the carbon that has the most substituents.
Answer:
Losing 2 valence electrons
Gaining 2 electrons
That would be cause part of the sodium is pure and that means it still kind of has it properties when it was an element and that its i think.
