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Lady bird [3.3K]
3 years ago
14

A spectral line has a wavelength of 7.35 *10-7 m. What is the energy of this radiation?

Chemistry
1 answer:
antoniya [11.8K]3 years ago
8 0

Answer:

2.7 x 10^-19 J

Explanation:

The formula needed for this problem is

E = hν

where E = energy, h = Planck's constant = 6.626x10^-34 and ν is the frequency

c = λν

where c = speed of light = 3x10^8, and λ = wavelength

3x10^8 = 7.35x10^-7 . ν

ν = 4.08 x 10^14 Hz

E = 6.626x10^-34 . 4.08x10^14 = 2.7 x 10^-19 J

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The unfortunate firefly hitting the bus does not change the velocity of the bus very much. Technically there is a change, but it's so very small and miniscule that it barely registers. To any casual observer not paying very close attention, they don't notice anything at all. So effectively the force on the firefly is a lot greater since the firefly got the worst end of the deal.

So in short, we look at the velocity of each object and see which velocity changed the most. In this case, the firefly's velocity changed from whatever speed it was flying to 0 when it stops flying all together. That's why the force is greater on the bug.

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Copper is an example of a(n) __________.
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The answer is D. element

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3 years ago
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Carbon burns with oxygen to produce carbon dioxide gas what is the correct way to write the chemical reaction
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What is the number of electrons shared between the atoms in I2 molecule (That is an i not a 1)
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3 years ago
Excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide to produce aqueous sodium nitrate and copper(II) sulfide as
nikitadnepr [17]

The question in incomplete, complete question is;

Determine the theoretical yield:

Excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide to produce aqueous sodium nitrate and copper(II) sulfide as a precipitate. In this reaction 469 grams of copper(II) nitrate were combined with 156 grams of sodium sulfide to produce 272 grams of sodium nitrate.

Answer:

The theoretical yield of sodium nitrate is 340 grams.

Explanation:

Cu(NO_3)_2(aq)+Na_2S(aq)\rightarrow 2NaNO_3(aq)+CuS(s)

Moles of copper(II) nitrate = \frac{469 g}{187.5 g/mol}=2.5013 mol

Moles of sodium sulfide = \frac{156 g}{78 g/mol}=2 mol

According to reaction, 1 mole of copper (II) nitrate reacts with 1 mole of sodium sulfide.

Then 2 moles of sodium sulfide will react with:

\frac{1}{1}\times 2mol= 2 mol of copper (II) nitrate

As we can see from this sodium sulfide is present in limiting amount, so the amount of sodium nitrate will depend upon moles of sodium sulfide.

According to reaction, 1 mole of sodium sulfide gives 2 mole of sodium nitrate, then 2 mole of sodium sulfide will give:

\frac{2}{1}\times 2mol=4 mol sodium nitrate

Mass of 4 moles of sodium nitrate :

85 g/mol × 4 mol = 340 g

Theoretical yield of sodium nitrate = 340 g

The theoretical yield of sodium nitrate is 340 grams.

7 0
3 years ago
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