3 years ago

List two applications of electrostatics.

1 answer:

4 0

Atmospheric electricity and storms,electric current in a vacuum,spark discharge,electrostatic control filters and industrial electrostatic separation <- those are just a few

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A 4.0-kg object moving at 3.0 m/s experiences a 16.0-Newton resistive force over a duration

sveta [45]

Answer:

D is the answer hope you it helps you

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3 years ago

Name one non-metal that is a good conductor and why??

Vesna [10]

Answer:

silver

Explanation:

It is because it contains a higher number of movable atoms ( free electrons)

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2 years ago

A wire 3.22 m long and 7.32 mm in diameter has a resistance of 11.9 mΩ. A potential difference of 33.7 V is applied between the

Scorpion4ik [409]

Answer:

(a) Current is 2831.93 A

(b) $8.40A/m^2$

Explanation:

Length of wire l = 3.22 m

Diameter of wire d = 7.32 mm = 0.00732 m

Cross sectional area of wire

$A=\pi r^2=3.14\times 0.00366^2=4.20\times 10^{-5}m^2$

Resistance $R=11.9mohm=11.9\times 10^{-3}ohm$

Potential difference V = 33.7 volt

(A) current is equal to

$i=\frac{V}{R}=\frac{33.7}{11.9\times 10^{-3}}=2831.93A$

(B) Current density is equal to

$J=\frac{i}{A}$

$J=\frac{2831.93}{4.20\times 10^{-5}}=8.40A/m^2$

$R=\frac{\rho l}{A}$

$11.9\times 10^{-3}=\frac{\rho \times 3.22}{4.20\times 10^{-5}}$

$\rho =15.52\times 10^{-9}ohm-m$

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3 years ago

The amount of work done depends on what two things

fomenos

mass and acceleration have a nice day

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=See%20%5C%3A%20%20Attachment.%20%20%5C%3A%20" id="TexFormula1" title="See \: Attachment. \:

Tcecarenko [31]

So acceleration = (final velocity - initial velocity)/time

So (fv-iv)/t=a

(45-110)/4.5

Gives you (-130/9)km/h^2

You may have to convert the SI units so just follow my steps and change what must be changed

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3 years ago

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