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Diano4ka-milaya [45]
3 years ago
13

List two applications of electrostatics.

Physics
1 answer:
Tems11 [23]3 years ago
4 0
Atmospheric electricity and storms,electric current in a vacuum,spark discharge,electrostatic control filters and industrial electrostatic  separation <- those are just a few
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According to the Doppler Effect, which statement is true about a sound as it approaches you and then moves away.
sukhopar [10]

Answer:

A) As the source approaches you, the waves are compressed so that the pitch of the noise increases.  

Explanation:

The Doppler Effect occurs when there is relative motion between an observer and the source of a wave. When this happens, there is an apparent shift in the frequency of the wave, as perceived by the observer. In particular, two situations can occur:

1- If the source of the wave is moving towards the observer, the waves are compressed, so that the wavelength of the wave decreases, and therefore the frequency (and so the pitch) increases

2- If the source of the wave is moving away from the observer, the waves are stretched, so that the wavelength of the wave increases, and therefore the frequency (and so the pitch) decreases

An example of Doppler Effect occurs when we hear the sound of the siren of an ambulance.

In this problem, the situation described is situation 1 (sound waves is approaching the observer), so according to the explanation above, the correct answer is

A) As the source approaches you, the waves are compressed so that the pitch of the noise increases.

3 0
4 years ago
Read 2 more answers
Using the picture below, what is the displacement of the triangle?
zavuch27 [327]

Answer:

i think it is 40 kilometers in the positive direction... if not im sorry

Explanation:

7 0
3 years ago
A 1.7-kg firework is fired from the ground straight up on a planet with whose acceleration due to gravity is 4.8 m/s/s. You want
Sunny_sXe [5.5K]

Answer:

41.0 m/s, 10.6 s

Explanation:

Given:

a = -4.8 m/s²

Δy = 165 m

v = -10.0 m/s

Find: v₀ and t

v² = v₀² + 2aΔy

(-10.0 m/s)² = v₀² + 2(-4.8 m/s²) (165 m)

v₀ = 41.0 m/s

Δy = vt − ½ at²

165 m = (-10.0 m/s) t − ½ (-4.8 m/s²) t²

165 = -10t + 2.4t²

0 = 2.4t² − 10t − 165

Solve with quadratic formula:

t = [ -(-10) ± √((-10)² − 4(2.4)(-165)) ] / 2(2.4)

t = (10 ± √1684) / 4.8

t = 10.6 s

4 0
3 years ago
A tennis ball travelling at a speed of 46m/s with a mass of 58kg. Calculate the kinetic<br>energy​
Zanzabum

Answer:

its 1/2 the mass of the object times by its velocity ^ 2

7 0
3 years ago
A 3.00-kg object has a velocity 16.00 i ^ 2 2.00 j ^2 m/s.
trapecia [35]

Answer:

390 J

Explanation:

m = 3 kg

u = 16 i + 2 j

(a) Magnitude of velocity = \sqrt{16^{2}+2^{2}} = 16.1245 m/s

KEi = 1/2 m v^2 = 0.5 x 3 x 16.1245 = 390 J

(b) v = 18 i + 14 j

Magnitude of velocity =  \sqrt{18^{2}+14^{2}} = 22.804 m/s

KEf = 1/2 m v^2 = 0.5 x 3 x 22.804 = 780 J

According to the work energy theorem

Work done = change in KE = KEf - KEi = 780 - 390 = 390 J

8 0
4 years ago
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