Answer:
vf = √(vi²+2*(F/m)*D)
Explanation:
Given
Mass of the particle: M
Initial speed of the particle: vi
Force: F
Distance: D
We can apply the formula
F = M*a ⇒ a = F/m
then we use the equation
vf = √(vi²+2*a*D)
⇒ vf = √(vi²+2*(F/m)*D)
K=1/2 mv2
M=?
41.6kj convert to joules by multiplying by 1000 so it will be 41,600J because the unit of kinetic energy is in joules.
41,600=1/2(m)(8)
Arrange the equation it will be:
M= 41,600/4 = 10,400
Final answer is:
m= 10,400 kg
Answer:
(A) The maximum height of the ball is 40.57 m
(B) Time spent by the ball on air is 5.76 s
(C) at 33.23 m the speed will be 12 m/s
Explanation:
Given;
initial velocity of the ball, u = 28.2 m/s
(A) The maximum height
At maximum height, the final velocity, v = 0
v² = u² -2gh
u² = 2gh

(B) Time spent by the ball on air
Time of flight = Time to reach maximum height + time to hit ground.
Time to reach maximum height = time to hit ground.
Time to reach maximum height is given by;
v = u - gt
u = gt

Time of flight, T = 2t

(C) the position of the ball at 12 m/s
As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.
v² = u² - 2gh
12² = 28.2² - 2(9.8)h
12² - 28.2² = - 2(9.8)h
-651.24 = -19.6h
h = 651.24 / 19.6
h = 33.23 m
Thus, at 33.23 m the speed will be 12 m/s
Answer:
there is not enough information