If a planet has a non-circular orbit around a star, as the planet moves closer towards a star its orbital speed ….
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To solve this problem we will apply the concepts related to pressure, depending on the product between the density of the fluid, the gravity and the depth / height at which it is located.
For mercury, density, gravity and height are defined as
For the air the defined properties would be
We have for equilibrium that
Replacing,
Rearranging to find
Therefore the elevation of the mountain top is 9400ft
Answer:
The maximum height the pebble reaches is approximately;
A. 6.4 m
Explanation:
The question is with regards to projectile motion of an object
The given parameters are;
The initial velocity of the pebble, u = 19 m/s
The angle the projectile path of the pebble makes with the horizontal, θ = 36°
The maximum height of a projectile, , is given by the following equation;
Therefore, substituting the known values for the pebble, we have;
Therefore, the maximum height of the pebble projectile, ≈ 6.4 m.
Answer: 0.5N
Explanation: if the system is at equilibrium, sum of the torque will be equal to zero.
But if they are not in equilibrium.
U will find the difference in the two torque
find the attached file for solution
