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Karolina [17]
3 years ago
7

Place the following covalent bonds in order from least to most polar: a. H-Cl b. H-Br c. H-S d. H-C

Chemistry
1 answer:
timofeeve [1]3 years ago
7 0

Answer:


The Order is as follow,

                                     C-H < S-H < H-Br < H-Cl


Explanation:

                      Polarity depends on the electronegativity difference between two atoms, greater the electronegativity difference, greater will be the polarity of bond and vice versa.


Electronegativity Difference between Hydrogen and other given elements are as follow,


1) C-H;

               E.N of Carbon     = 2.55

               E.N of Hydrogen = 2.20

                                           ------------

               Difference              0.35


2) S-H;

               E.N of Sulfur       = 2.58

               E.N of Hydrogen = 2.20

                                           ------------

               Difference               0.38


3) H-Br;

               E.N of Bromine   = 2.96

               E.N of Hydrogen = 2.20

                                          -------------

               Difference              0.76


4) H-Cl;

               E.N of Chlorine   = 3.16

               E.N of Hydrogen = 2.20

                                           -----------

               Difference               0.96


Hence it is proved that the greatest electronegativity difference is found between H and Chlorine in H-Cl, therefore it is highly polar bond and vice versa.

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In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to anot
forsale [732]

The given question is incomplete . The complete question is :

In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to another. What are the new relative charges between the two atoms?

a. The giving atom and receiving atom are both negatively charged

b. The giving atom is now positively charged and the receiving atom is now negatively charged.

c. The giving and receiving atom are both positively charged

d. The giving atom is now negatively charged and the receiving atom is now positively charged.

Answer:  The giving atom is now positively charged and the receiving atom is now negatively charged.

Explanation:

Ionic compounds are formed by transference of electrons between metals and non metals. The bond formed between a metal and a non-metal is always ionic in nature.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Thus when  one electron moves from one atom to another, the metal acquires a positive charge and the non metal acquires negative charge.

For example:  NaCl is formed by transfer of one electron from sodium to chlorine , thus forming Na^+ and Cl^-

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3 years ago
The blue color of the sky results from the scattering of sunlight by air molecules. The blue light has a frequency of about 7.5
vazorg [7]

A) c = 3 x 10^8 m/s 
f = 7.15 x 10^14 Hz 
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B) E = h  f 
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E = 6.63 x 10^-34 x 7.15 x 10^14 = 4.74 x 10^-19 J

Read more on Brainly.com - brainly.com/question/5760368#readmore
3 0
3 years ago
How does mass affect potential energy?
Andreyy89

What i would say: The amount of gravitational potential energy an object has depends on its height and mass. The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds. Gravitational potential energy increases as weight and height increases.

Hope this helps! :)

8 0
3 years ago
PCl3(g) + Cl2(g) ⇋ PCl5(g) Kc = 91.0 at 400 K. What is the [Cl2] at equilibrium if the initial concentrations were 0.24 M for PC
Dmitry_Shevchenko [17]

Answer:

[Cl₂] in equilibrium is 1.26 M

Explanation:

This is the equilibrium:

PCl₃(g) + Cl₂(g) ⇋ PCl₅(g)

Kc = 91

So let's analyse, all the process:

                PCl₃(g)        +        Cl₂(g)     ⇋        PCl₅(g)

Initially     0.24 M                 1.50M                 0.12 M

React           x                           x                         x

Some amount of compound has reacted during the process.

In equilibrium we have

              0.24 - x                  1.50 - x                  0.12 + x

As initially we have moles of product, in equilibrium we have to sum them.

Let's make the expression for Kc

Kc = [PCl₅] / [Cl₂] . [PCl₃]

91 = (0.12 + x) / (0.24 - x) ( 1.50 - x)

91 = (0.12 + x) / (0.36 - 0.24x - 1.5x + x²)          

91 (0.36 - 0.24x - 1.5x + x²) = (0.12 + x)

32.76 - 158.34x + 91x² = 0.12 +x

32.64 - 159.34x + 91x² = 0

This a quadratic function:

a = 91; b= -159.34; c = 32.64

(-b +- √(b² - 4ac)) / 2a

Solution 1 = 1.5

Solution 2 = 0.23 (This is our value)

So [Cl₂] in equilibrium is 1.50 - 0.23 = 1.26 M

5 0
4 years ago
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