<u>Answer:</u> The formula of chromic acid is 
<u>Explanation:</u>
We are given an ionic compound named as chromic acid. This acid is formed by the combination of hydrogen ion and chromate ion.
An acid is defined as the substance which releases hydrogen ion when dissolved in water.
Hydrogen is the 1st element of periodic table having electronic configuration of
.
This element will loose 1 electron to form
ion.
Chromate ion is a polyatomic ion having chemical formula of 
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
So, the chemical formula for the given compound is 
Thus, the formula of chromic acid is 
Answer:
Mass = 427.05 g
Explanation:
Given data:
Formula units of sodium chloride = 4.38 ×10²⁴
Mass of NaCl = ?
Solution:
One mole contain formula units = 6.022 ×10²³
4.38×10²⁴ formula units × 1mol /6.022 ×10²³ formula units
0.73 ×10¹ mol
7.3 mol
Mass of NaCl:
Mass = number of moles × molar mass
Mass = 7.3 mol × 58.5 g/mol
Mass = 427.05 g
Answer is "The salt Bridge"
Explanation:
During the spontaneous reaction in Voltaic Cell, the balance of ions get disturb due to increase in concentration of negative charge in one half cell and positive charge in another. In order to keep balance the charges in cell, concentration of ions on both sides and overall neutrality of the system, a U-shape tube filled with inert electrolyte is connected to both half cells. The electrolyte migrates in such a way that the charges of solution in cells keep constant.
Answer:
[H3O+] = 1.4*10^-5 M
pH = 4.85
[OH-] = 7.08*10^-10
Explanation:
As pH is a measure of hydronium H3O concentration, simply substitute [H3O+] into the following equation:
pH = -log[H+]
pH = -log(1.4*10^-5)
pH = 4.853871...
Round to 2-3 sig figs due to only being given data with 2 significant figures
pH = 4.85
One method to get to [OH-] is to turn pH into pOH and then use inverse functions to get [OH-]
pH + pOH = 14
4.85 + pOH = 14
pOH = 9.15
Then to get [OH-] from pOH:
pOH = -log[OH-]
9.15 = -log[OH-]
-9.15 = log[OH-]
10^(-9.15) = [OH-]
7.07945784 * 10^-10 = [OH]
Round based on given significant figures again:
7.08*10^-10 = [OH-]
(Feel free to add any questions & I'll be sure to reply if clarification is needed)