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3 years ago

Si se adiciona etilenglicol (compuesto no volátil) a agua destilada:

Chemistry

1 answer:

poizon [28]3 years ago

6 0

Answer:

Hey hi

Explanation:

Can you pls tell me which language is this pls I really want to help you... Sorry

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Which of the following are always larger than the neutral atoms from which they are formed?

Anuta_ua [19.1K]

Answer:

A) Cations

Explanation:

a) Cations have a positive charge and are larger than their neutral counterparts!

b) Anions have a negative charge and are smaller than their neutral counterparts

c) Metals can have either a positive or negative charge making it either a cation or an anion

d) Carbon is an element and it can have a charge anywhere from +4 to -4

A good way to remember that cations are positive is to think that CATions are always PAWSitive! ^-^

3 0

3 years ago

How many molecules of excess reactant remain after the reaction is complete?

vazorg [7]

8

It’s 8 bc I said it was 8 ;)

5 0

3 years ago

3/4(x-2)=x-1 please answer me

Elan Coil [88]

Answer:

-2

Explanation:

3/2 (x-2) = x-1

<=> 3/4 x - 3/2 = x-1

<=> 3/4 x - x = 3/2 -1

<=> -1/4 x =1/2

<=> x= -2

3 0

3 years ago

Read 2 more answers

1) Given the balance equation below. Calculate how much Na3PO4 in grams you

juin [17]

Answer:

<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.

Explanation:

The balanced equation:

$Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}$

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

$\frac{164}{120}$

100 grams of NaOH is produced from =

$\frac{164}{120}\times100$ gram of Na3PO4

calculate,

= 136.67 g

8 0

3 years ago

The gas phase reaction, A2 + B2 ---->2AB, proceeds by bimolecular collisions between A2 and B2 c,o(\'e'9 molecules. The rate

Varvara68 [4.7K]

Answer:

The reaction rate becomes quadruple.

Explanation:

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.

Thus,

Given that:- The rate law is:-

$r=k[A_2][B_2]$

Now, $[A'_2]=2[A_2]$ and $[B'_2]=2[B_2]$

So, $r'=k[A'_2][B'_2]=k\times 2[A_2]\times 2[B_2]=4\times k[A_2][B_2]=4r$

<u>The reaction rate becomes quadruple.</u>

5 0

3 years ago