Answer:
The question has some details missing which I have shown in the attached file.
Explanation:
The concept of arrehenius equation is used to calculate the activation energy.
- Given T1 = 141.0 degree celsius = 414K and K1 = 3.3 x 10^8
- T2 = 77 degree celsius = 350K and k2 = 1.1 x 10^8
- from Arrehenius equation;
- ln(k2/k1) = -Ea/R [1/T2 - 1/T1]
- ln(1.1/3.3) = -Ea/8.314 [ 1/350 - 1/414]
- Ea = 20.679KJ/mol = activation energy for this reaction
Answer: By shifting the equilibrium to align with the interest of the company.
Explanation: Major production companies depend on the principle of chemical equilibrium to normalize their production depending on their interests. This principle is called Le Chatelier's principle.
The major concern of Chemical industries is their output and production time. Knowledge of Chemical equilibrium can help to maximize the output in a relatively less time by considering some factors.
Factors such as Temperature, Pressure, Concentration, and Catalyst presence can change the chemical equilibrium to benefit companies.
Answer:
Why ? Because 1 molecule of H2SO4 gives 2 H+ ions per molecule while only one H+ ion is required to neutralize 1 molecule of KOH. So, 1 molecule of H2SO4 can neutralize 2 molecules of KOH. Hence, we would require 525 ml of 0.03 M H2SO4 to neutralize 525 ml of 0.06 M KOH. How will we prepare 525 ml of 0.03 M H2SO4 ?
Explanation:
Now, we have 0.025 M H2SO4 and we do not know how much volume we have.
We will use the standard N1 X V1 = N2 X V2 for this calculation.
N1=0.025 M; V1=unknown; N2=0.03 M and V2=525 ml.
So V1= (0.03 X 525)/(0.025) = 630 ml.
Answer:
4Cr + 3O2 —> 2Cr2O3
Explanation:
Information from the question include:
Chromium + oxygen -> chromium(III) oxide
From the word equation given above, the equation can be written as follow:
Cr + O2 —> Cr2O3
The equation can be balance by doing the following:
There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 2 in front of Cr2O3 and 3 in front of O2 as shown below:
Cr + 3O2 —> 2Cr2O3
Now, we have 4 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 4 in front of Cr as shown below:
4Cr + 3O2 —> 2Cr2O3
Now the equation is balanced
Answer:The formulas of ionic compounds are:
a)
b)
c)
d)
Explanation:
Formulas for the an ionic compounds is determine by:
Criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
(a) Copper bromide :Given that it contains 
ion.
(b) Manganese oxide : Given that it contains 
ion.
(c)Mercury iodide :Given that it contains 
(d) Magnesium phosphate :Given that it contains 
