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melomori [17]
3 years ago
9

Arrange the metals used in this experiment (including H2 and Ag) in order of decreasing reactivity (most reactive metal first).

The metals to be included are Ag, Al, Ca, Cu, Fe, H2, Mg, Na, Pb, Sn, and Zn.
Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Explanation:

According to the reactivity series chart, elements from high to lower reactivity are arranged as follows.

    K, Na, Ca, Mg, Al, C, Zn, Fe, Sn, Pb, H, Cu, Ag, Au

So, using this standard reactivity chart of metals we will place the given metals in the order of decreasing reactivity as follows.

     Na > Ca > Mg > Al > Zn > Fe > Sn > Pb > H_{2} > Cu > Ag

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Calculate the work (kJ) done during a reaction in which the internal volume contracts from 85 L to 12 L against an outside press
butalik [34]

Answer:

The work done on the system is 17.75_KJ

Explanation:

To solve this question we need to know the required equations from the given variables, thus

Initial volume = 85L

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work done = - PΔV

2.4×(85-12) = 175.2L×atm

Converting from L•atm to KJ is given by

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(175.2 L•atm) * (0.1013 kJ / 1 L•atm)

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5 0
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Part A
abruzzese [7]

117 mL of 0.210 M K₂S solution

Explanation:

The question asks about the volume of 0.210 M K₂S (potassium sulfide) solution required to completely react with 175 mL of 0.140 M Co(NO₃)₂ (cobalt(II) nitrate).

We have the chemical reaction:

K₂S + Co(NO₃)₂ → CoS + 2 KNO₃

molar concentration = number of moles / volume (L)

number of moles = molar concentration × volume

number of moles of Co(NO₃)₂ = 0.140 × 175 = 24.5 mmoles

We see from the chemical reaction that 1 mmole of Co(NO₃)₂ is reacting with 1 mmole of K₂S, so 24.5 mmoles of Co(NO₃)₂ are reacting with 24.5 mmoles of K₂S.

volume = number of moles / molar concentration

volume of K₂S solution = 24.5 / 0.210 = 117 mL

Learn more about:

molar concentration

brainly.com/question/2767031

brainly.com/question/8858482

#learnwithBrainly

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3 years ago
What's the difference between mass and weight?
eduard

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Explanation:

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Potassium -39 has how many neutrons
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Hope this helps
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