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melomori [17]
4 years ago
9

Arrange the metals used in this experiment (including H2 and Ag) in order of decreasing reactivity (most reactive metal first).

The metals to be included are Ag, Al, Ca, Cu, Fe, H2, Mg, Na, Pb, Sn, and Zn.
Chemistry
1 answer:
LUCKY_DIMON [66]4 years ago
4 0

Explanation:

According to the reactivity series chart, elements from high to lower reactivity are arranged as follows.

    K, Na, Ca, Mg, Al, C, Zn, Fe, Sn, Pb, H, Cu, Ag, Au

So, using this standard reactivity chart of metals we will place the given metals in the order of decreasing reactivity as follows.

     Na > Ca > Mg > Al > Zn > Fe > Sn > Pb > H_{2} > Cu > Ag

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Determine the molarity of 1.2 mol KCl in 1.1 L of a solution?
victus00 [196]

Answer:

1.1 M

General Formulas and Concepts:

  • Molarity = moles of solute / liters of solution

Explanation:

<u>Step 1: Define variables</u>

1.2 mol KCL

1.1 L of solution

M = unknown

<u>Step 2: Solve for Molarity</u>

  1. Substitute:                    M = 1.2 mol/1.1 L
  2. Evaluate:                       M = 1.09091

<u>Step 3: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

1.09091 M ≈ 1.1 M

7 0
3 years ago
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6 0
3 years ago
The standard molar enthalpy of formation of NH3(g) is -45.9 kJ/mol. What is the enthalpy change if 9.51 g N 2(g) and 1.96 g H2(g
pogonyaev

Answer:

a. -29.8 kJ/mol-rxn

Explanation:

For a chemical reaction system the forward and reverse rate are equal. The standard molar enthalpy formation of NH3 is -45.9 kJ/mol. For the enthalpy of NH3 (8) the molar enthalpy is -29.8kJ/mol. The molar mass of N2 = 28.02g/mol. Molar enthalpy of formation is standard amount of substance produced in the formation of a reaction. The molar enthalpy is the change in enthalpy due to reaction per mole.

6 0
3 years ago
Determine the number of atoms of each element in the empirical formula of a compound with the following composition:
34kurt
To determine the empirical formula of the compound, we assume a basis of 100 g of this compound. We calculate as follows:

C = 68.75 g
H = 10.90 g
O = 20.35 g

We convert these mass to moles,
C = 68.75 g / 12.01 g/mol = 5.72 mol
H = 10.90 g / 1.01 g/mol = 10.79 mol
O = 20.35 g / 16 g/mol = 1.27 mol

C = 5.72 mol / 1.27 mol = 5
H = 10.79 mol / 1.27 mol = 8
O = 1.27 mol / 1.27 mol = 1

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6 0
3 years ago
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The Diameter of a chlorine atom is 200. Pm. How many chlorine atoms are required to line up end to end to stretch a distance of
Artist 52 [7]
Diameter = 200pm
200pm -> mm
200pm *^-12 / 1*10^-3 = .0000002
2.0*10-7x mm = 1.0mm
Divide x on both sides

6 0
3 years ago
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