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skelet666 [1.2K]
3 years ago
14

Where did the noble gases get their name

Chemistry
1 answer:
blsea [12.9K]3 years ago
6 0
Noble means chemically inert.
That is one way.
It is group 8 and doesn't react with atoms because it is stable.<span />
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Determine the molecular geometry based on the description of bonding and lone pairs of electrons around the central atom. Three
Inessa05 [86]

Answer:

Three double bonds and no lone pairs of electrons- trigonal planar

Two single bonds and two lone pairs of electrons-bent

Five single bonds and no lone pairs of electrons- trigonal bipyramidal

Three single bonds and one lone pair of electrons- trigonal pyramidal

Two double bonds and no lone pairs of electrons - linear

Four single bonds and no lone pairs of electrons- tetrahedral

Six single bonds and no lone pairs of electrons- octahedral

Explanation:

The valence shell electron pair repulsion theory gives a description of the shape of a molecule based on the number of regions of electron density present on the valence shell of the central atom of the molecule.

The molecules are distorted away from the shape predicted on the basis of the VSEPR by the presence of lone pairs on the valence shell of the central atom in the molecule. In the absence of lone pairs, the shape of a molecule is exactly the shape predicted on the basis of the VSEPR theory.

5 0
2 years ago
The energy available to primary consumers in an energy pyramid is 800 kilocalories. Approximately how much energy is used by the
ki77a [65]
The answer is B, Let me know if you get it right!
5 0
3 years ago
Read 2 more answers
An ideal gas (C}R), flowing at 4 kmol/h, expands isothermally at 475 Kfrom 100 to 50 kPa through a rigid device. If the power pr
Zina [86]

<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

We are given:

C_p=\frac{7}{2}R\\\\T=475K\\P_1=100kPa\\P_2=50kPa

Rate of flow of ideal gas , n = 4 kmol/hr = \frac{4\times 1000mol}{3600s}=1.11mol/s    (Conversion factors used:  1 kmol = 1000 mol; 1 hr = 3600 s)

Power produced = 2000 W = 2 kW     (Conversion factor:  1 kW = 1000 W)

We know that:

\Delta U=0   (For isothermal process)

So, by applying first law of thermodynamics:

\Delta U=\Delta q-\Delta W

\Delta q=\Delta W      .......(1)

Now, calculating the work done for isothermal process, we use the equation:

\Delta W=nRT\ln (\frac{P_1}{P_2})

where,

\Delta W = change in work done

n = number of moles = 1.11 mol/s

R = Gas constant = 8.314 J/mol.K

T = temperature = 475 K

P_1 = initial pressure = 100 kPa

P_2 = final pressure = 50 kPa

Putting values in above equation, we get:

\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

4 0
2 years ago
The 3 components of air
jok3333 [9.3K]

Nitrogen (around 78%), Oxygen (around 21%), and Argon (around 1%).

Hope this helps :)

8 0
2 years ago
Read 2 more answers
What is the density of object A? Does it sink<br> or float in water?
Oksana_A [137]

Answer:

~1.5 g/cm3 and it does NOT float in water.

Explanation:

If you look at the graph, Object A weighs ~6 grams and is ~4 cm3 in volume

Density = Mass/Volume

So 6 grams/4 cm3 = 1.5 g/cm3

Water has a density of 1 g/cm3 and because Object A density is higher than that of water, it sinks.

:)

3 0
2 years ago
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