1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SVETLANKA909090 [29]
3 years ago
11

2CO(g)+O2 (g) =2CO2(g)

Chemistry
1 answer:
Ronch [10]3 years ago
4 0

Answer:

6.76 moles.

Explanation:

2CO(g)+O2 (g) =2CO2(g)

When 2 CO mols were reacted with excess O2 then 2 mols of CO2 is created.

Therefore if 6.76 moles reacted, same number of CO2 will be created.

You might be interested in
Planck’s constant relates the joules of energy absorbed/released by matter to the ________. atomic number of the element frequen
mamaluj [8]

<span>Planck’s constant relates the joules of energy absorbed/released by matter to the wave frequency f. the plancks constant was first recognized in 1900 by Max Planck. The equation that relates the joules of energy absorbed/released by matter to the wave frequency f is called the plancks-eintein relation, E = hf</span>

5 0
3 years ago
8. Which of the following compounds is an ionic compound? (metal)
fomenos
The answer is b, because all of the other compounds are covelent
6 0
3 years ago
Read 2 more answers
n the periodic table, the atomic mass of oxygen is listed as 15.9994 amu. Based on this, one can deduce that the most common ___
Anit [1.1K]
Isotope- variation of an element

Sixteen- atomic number of oxygen
4 0
3 years ago
Read 2 more answers
What factors affect the difference in the color of the stars
MAVERICK [17]

Answer:

My answer is Temperature

3 0
3 years ago
The half-life of Co-59 is 35 days. How much of a 610.0-gram sample will remain after 140 days?
vitfil [10]

Answer:

Amount left after 140 days is 38.125 g.

Explanation:

Given data:

Half life of Co-59 = 35 days

Total mass of sample = 610.0 g

Sample remain after 140 days = ?

Solution:

Number of half lives passes during 140 days:

Number of half lives  = T elapsed / Half lives

Number of half lives  = 140 days / 35 days

Number of half lives  = 4

Amount left:

At time zero = 610 g

At first half life = 610 g/2 = 305 g

At second half life = 305 g/2 = 152.5 g

At 3rd half life = 152.5 g/2 = 76.25 g

At 4th half life = 76.25 g /2 =38.125 g

Amount left after 140 days is 38.125 g.

3 0
3 years ago
Other questions:
  • During a lab activity, students prepared two solutions separately at the same temperature. Later they mixed the solutions and th
    7·1 answer
  • A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th
    11·2 answers
  •     Which of these is considered a cation
    6·1 answer
  • How many moles is 24 grams of carbon?
    14·2 answers
  • Please draw the resonance structure for this compound indicating formal charges and lone pairs
    6·1 answer
  • Limiting Reactant Worksheet
    7·1 answer
  • Choose the products that complete the reaction. The chemical equation may not be balanced.
    5·2 answers
  • a few drops of perfume were spilt on the floor a few minutes later ghe perfume could be smelt a few meters away what 2 processes
    15·1 answer
  • 20 points
    11·1 answer
  • They all have the same choices but one of them its not gonna be used.​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!