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SVETLANKA909090 [29]
3 years ago
11

2CO(g)+O2 (g) =2CO2(g)

Chemistry
1 answer:
Ronch [10]3 years ago
4 0

Answer:

6.76 moles.

Explanation:

2CO(g)+O2 (g) =2CO2(g)

When 2 CO mols were reacted with excess O2 then 2 mols of CO2 is created.

Therefore if 6.76 moles reacted, same number of CO2 will be created.

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Because it has no <span> stereogenic carbon centres.</span>
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3 years ago
Which statement describes a reason to consider air a mixture? A) The major constituents of air are gaseous elements. B) The comp
umka21 [38]

The correct answer is - A) The major constituents of air are gaseous elements.

With the statement ''the major constituents of air are gaseous elements'' we can easily conclude that the air is a mixture. The reason for that is that we have a plural usage of the word element, elements, which mean that there are multiple elements that make up the air.

The air is indeed predominantly a mixture of gaseous elements. The most abundant gas in the air being the nitrogen with 78.9%, oxygen with 20.95%, argon 0.93%, and carbon dioxide 0.04%, with lesser amounts of other gases also be present in it. The water vapor is also present in the air, though it is variable, being around 1% at sea level, but only 0.4% over the entire atmosphere.

3 0
3 years ago
State what would be observed when the following pairs of reagents are mixed in a test tube.
Mandarinka [93]

Answer:

(i). C6H2COOH and Na2CO3(aq)

observation: <u>Bubbles</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>colourless</u><u> </u><u>gas</u><u> </u><u>(</u><u>carbon</u><u> </u><u>dioxide</u><u> </u><u>gas</u><u>)</u>

(ii) CH3CH2CH2OH and KMnO4 /H

observation: <u>The</u><u> </u><u>orange</u><u> </u><u>solution</u><u> </u><u>turns</u><u> </u><u>green</u><u>.</u>

[<em>This</em><em> </em><em>is</em><em> </em><em>because</em><em> </em><em>oxidation</em><em> </em><em>of</em><em> </em><em>propanol</em><em> </em><em>to</em><em> </em><em>propanoic</em><em> </em><em>acid</em><em> </em><em>occurs</em>]

(iii) CH3CH2OH and CH3COOH + conc. H2SO4

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[<em>This</em><em> </em><em>is</em><em> </em><em>because</em><em> </em><em>an</em><em> </em><em>ester</em><em>,</em><em> </em><em>diethylether</em><em> </em><em>is</em><em> </em><em>formed</em><em>]</em>

(iv) CH3CH = CHCH3 and Br2 /H2O

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4 0
3 years ago
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i hope this helps :)

3 0
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irga5000 [103]

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Enriched uranium is the fuel source is not the precaution taken at the nuclear power plant to ensure safety because it is just explaining the fact that the uranium is the source of radiation. All other factors such as safety systems are built into them, all parts are kept in good repair and processes are carefully monitored are relevant precautions.

8 0
3 years ago
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