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spayn [35]
2 years ago
5

When amino acids polymerize to make a protein, which of the following is produced as a byproduct?

Chemistry
2 answers:
vfiekz [6]2 years ago
5 0

Answer:

ssdadw

Explanation:

ssdadw

Lyrx [107]2 years ago
4 0

Answer:

Water is produced.

Explanation:

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5. A particular anticodon is 5'-AGC-3'. The codon that is a precise complementary base pair match for this is 5'-AGU-3'. However
Veseljchak [2.6K]

Explanation:

Wobble Hypothesis given by Francis Harry Compton Crick states that 3rd base of mRNA codon can base pair with 1st base of a tRNA anticodon undergoing non-Watson-Crick.

The first 2 bases of the mRNA codon form Hydrogen bonds with the corresponding bases on tRNA anticodon in Watson-Crick manner. Through this, they only form the base pairs with the complimentary bases. However, formation of the Hydrogen bonds between 3rd base on codon and 1st base on anticodon can occur potentially in non-Watson-Crick manner.  

<u>Thus, the Wobble Hypothesis explains that why the multiple codons can code for single amino acid.</u>

3 0
3 years ago
Explain some of the benefits and problem associated with the pesticide DDT.
Dafna1 [17]

Some benefits are that DDT helps us grow crops and keeps pests off our crops.

But DDT is harmful to the environment. If it gets into the water ways then if can harm fish and animals that eat the fish such as birds.

4 0
2 years ago
Find the empirical formula of the following compounds:
Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus \frac{mol phosphorus}{ 30.97 g phosphorus}= 0.0293 mol

Moles bromine 6.99 g bromine\frac{mol bromine}{79.90 g bromine}=0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

To learn more about empirical formula visit:

brainly.com/question/14044066

#SPJ4

8 0
1 year ago
It the mass of a material is 46 grams and the volume of the material is 8 cm ^3 What would the density of the material to be
Nat2105 [25]
5.75 Grams per cm^3

You do mass divided by volume
3 0
3 years ago
Whats the unit for mass
sesenic [268]

Answer:

The unit for mass is the kilogram (Kg).

Explanation:

Hope this helped!! <3 good luckk!!

5 0
3 years ago
Read 2 more answers
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