Answer:
72J
Explanation:
distance moved is equal to 3m.then just substitute x with 3m.
Fx = (14(3) - 3.0(3)2)) N
Fx =(42-18)N
Fx =24N
W=Fx *S
W=24N*3m
W=72J
Answer:
![a_{c}=v^{2}/R](https://tex.z-dn.net/?f=a_%7Bc%7D%3Dv%5E%7B2%7D%2FR)
The radius of curvature changes so that centripetal acceleration is similar along the entire roller coaster.
Explanation:
We know that the centripetal acceleration is directly proportional to the tangential velocity and inversely proportional to the radius of curvature:
![a_{c}=v^{2}/R](https://tex.z-dn.net/?f=a_%7Bc%7D%3Dv%5E%7B2%7D%2FR)
By energy conservation (and common sense), we know that the speed at the top of the roller coaster is smaller. Therefore if the roller coaster has similar accelerations (therefore also similar normal forces) at the top and at the bottom, it is necessary that the difference in speed be compensated with the radius of curvature, i.e. smaller radius at the top than at the bottom.
An example would be 2 types of motion. It could be rectilinear or projectile motion. There are various equations for each type. Since you don't want me to tell you the answer, I could just express it in words. Then, it will be up to you to translate into mathematical equations.
For rectilinear motion, the distance traveled is equal to the initial velocity times the time, plus one-half of the acceleration times the square of the time. For projectile motion, the maximum distance is equal to the square of the initial velocity multiplied with the square of the sine of the launch angle, all over twice the gravity.
Answer:
B) Blackbody radiation
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Answer: Buildings, walking or cycling
Explanation: Building would slide off of their foundations. If you were cycling then it just wouldn’t work, but if it was in the middle of moving then the brakes most likely won’t work.