At what vertical velocity should no object be launched at in order to achieve a height of 20m?
1 answer:
Answer:
19.8 m/s
Explanation:
Given:
Maximum vertical displacement of the object (H) = 20 m
Acceleration due to gravity (g) = 9.8 m/s²
At maximum height, the velocity of the object is 0 m/s for a moment. So, final velocity (v) at the maximum height is 0 m/s.
Now, let the initial velocity or velocity at launch be 'u' m/s.
Now, using the following equation of motion for vertical motion:
Rewriting in terms of 'u', we get:
Plug in the given values and solve for 'u'. This gives,
Therefore, the vertical velocity at the launch is 19.8 m/s.
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Answer:
The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s
Explanation:
From Newton's second law, F = mg and also from coulomb's law F= Eq
Dividing both equations by mass;
F/m = Eq/m = mg/m, then
g = Eq/m --------equation 1
Again, in a projectile motion, the time of flight (T) is given as
T = (2usinθ/g) ---------equation 2
Substitute in the value of g into equation 2
Charge of proton = 1.6 X 10⁻¹⁹ C
Mass of proton = 1.67 X 10⁻²⁷ kg
E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°
Solving for T;
T = 7.83 X10⁻⁷ s