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uysha [10]
3 years ago
12

At what vertical velocity should no object be launched at in order to achieve a height of 20m?​

Physics
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer:

19.8 m/s

Explanation:

Given:

Maximum vertical displacement of the object (H) = 20 m

Acceleration due to gravity (g) = 9.8 m/s²

At maximum height, the velocity of the object is 0 m/s for a moment. So, final velocity (v) at the maximum height is 0 m/s.

Now, let the initial velocity or velocity at launch be 'u' m/s.

Now, using the following equation of motion for vertical motion:

v^2=u^2-2gH

Rewriting in terms of 'u', we get:

u^2=v^2+2gH\\\\u=\sqrt{v^2+2gH}

Plug in the given values and solve for 'u'. This gives,

u=\sqrt{0+2\times 9.8\times 20}\\\\u=\sqrt{392}\\\\u=19.8\ m/s

Therefore, the vertical velocity at the launch is 19.8 m/s.

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A constant force of friction 50N is acting on a body of mass 200 Kg moving initially with a speed of 15 m/s. How long does the b
Zina [86]

Answer:

F=-50N

M=200kg

U=15m/s

F=Ma

a=F/M=-50/200=-0.25

V^2-U^2=2aS

0-(15)^2=2(-0.25)S

S=-225/-0.5=450m

V=U+at

0=15-0.25t

t=-15/-0.25=60s

Explanation:

Hope this helps, let me know if you have any questions!

Have a great day.

8 0
3 years ago
How much force would you need to cause a 20-kilogram object to accelerate in a straight line to 20 m/s2?
Yakvenalex [24]

Answer:

400N

Explanation:

Newton's second law of motion

F = ma

20 x 20 = F

F = 400

5 0
2 years ago
The current through a stationary loop in a constant magnetic field:
Angelina_Jolie [31]

Answer:

remains zero

Explanation:

According to the Faraday's law of electromagnetic induction, when the magnetic flux linked with the coil changes, an induced emf is developed in the coil.

Here the loop is kept stationary in a constant magnetic field, so no magnetic flux linked with the coil changes, hence the current remains zero in the coil.

7 0
3 years ago
An ice skater is preparing for a jump with turns and has his arms extended. His moment of inertia is 1.7 kg · m2 while his arms
serg [7]

Answer:

2 revolutions.

Explanation:

We need to obtain the angular velocity when he is in the air.

The angular momentum is given by:

L_1=I_1*\omega_1\\L_1=1.7kg.m^2*0.7rev/s*\frac{2\pi rad}{1rev}=7.5kg.m^2/s

Because of angular momentum conservation L1=L2, so the final angular velocity is given by:

\omega_2=\frac{L1}{I_2}=\frac{7.5kg.m^2/s}{0.7kg.m^2}=10.7rad/s

We need to calculate the time the skater is in the air, so we need to use the formula of parabolic motion:

y=y_o+v_y*t-\frac{1}{2}*g*t^2\\0=0+8.8m/s*sin(45^o)*t-4.9m/s^2*t^2\\0=6.22t-4.9t^2\\solving:\\t=1.26s\\t=0

so the time taken is 1.26s

the angular displacement is given by:

\theta=\omega*t\\\theta=13.5rad

the number of revolutions is given by:

rev=\frac{\theta}{2\pi}=\frac{13.5}{2\pi}=2.1rev

the skater execute two complete revolutions in the air.

7 0
3 years ago
Henery takes a boat ride for 15 mins to reach his destination. If the boat was traveling at 6meters/seconds,how far did the boat
Luba_88 [7]
I'm pretty sure its 5,400
7 0
3 years ago
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