What factors affect where a plant or animal lives

Which form of energy is associated with an object’s position?

dybincka [34]

Answer:

potential

Explanation:

4 0

3 years ago

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Place the single weight with a known mass on the spring and release it. Eventually, the weight will come to rest at an equilibri

aliya0001 [1]

Answer:

X=m*g/K

Explanation:

Since the elastic force of the spring is balancing the force of gravity:

Fe = m*g

Now, on the spring by Hook's law, the magnitude of the elastic force will be:

Fe = K*X where K is the elastic constant of the spring and X is the distance the spring is strectches measured from its original lenght to its current length.

Replacing this value:

K*X = m*g Solving for X:

X = m*g/K This value is directly proportional to the object's weight and inversely proportional to the spring's constant.

3 0

4 years ago

1) Consider a source particle of charge qS=9 C located at (−9,5) [distances in meters]. Find the electric field vector at the ta

xeze [42]

Answer:

1) E = 2.25 i^+ 0.809j^) 10⁹ N / C , 2) E = 2.39 10⁹ N / C , 3) θ = 19.8º , 4) F = 19.12 10⁹ N , 5) E = (1.32 i^+ 3.56 j^) 109 N/C

Explanation:

1) The equation for the electric field is

E = k q / r²

Where K is the Coulomb constant that is worth 8.99 10⁹ N m² /C², q is the load and r is the distance of the load to the test point

Since the electric field is a vector magnitude, we can find its component

X axis

Ex = k q / x²

where the distance on the axis is

x = √ (X₂-x₁)²

x = √ (-15 + 9)² = 6 m

Eₓ = 8.99 10⁹ 9/6²

Eₓ = 2.25 10⁹ N /C

Y Axis

y = √ (y₂-y₁)² = √ (15-5)² = 10 m

$E_{y}$ = 8.99 10⁹ 9/10²

$E_{y}$ = 0.809 10⁹ N / C

E = Eₓ i^+ $E_{y}$ j^

E = 2.25 i^+ 0.809j^) 10⁹ N / C

2) the magnitude can be found using the Pythagorean triangle

E = √ (Eₓ² + $E_{y}$ ²)

E = √ (2.25² + 0.809²) 10⁹

E = 2.39 10⁹ N / C

3) to find the angle let's use trigonometry

tan θ = $E_{y}$ / Eₓ

θ = tan⁻¹ $E_{y}$ / Eₓ

θ = tan⁻¹ (0.809 / 2.25)

θ = 19.8º

Regarding the positive side of the x axis

4) a charge q2 = 8C is placed, let's calculate the force

F = q E

F = 8 2.39 10⁹

F = 19.12 10⁹ N

5) The total electric field at the origin, let's look for its components

q₁ = 9C

r₁ = -9 i ^ + 5 j ^

q₂ = 8 C

r₂ = -15 i ^ + 15 j ^

X axis

Eₓ = E₁ₓ + E₂ₓ

Eₓ = k q₁ / Dx₁² + k q₂ / Dx₂²

Eₓ = 8.99 10⁹ (9 / (9-0)² + 8 / (15-0)²)

Eₓ = 1.32 109 N / A

Y Axis

$E_{y}$ = $E_{1y}$ + $E_{2y}$

$E_{y}$ = k q₁ / Δy₁² + k q₂ / Δy₂²

$E_{y}$ = 8.99 109 (9/5² + 8/15²)

$E_{y}$ = 3.56 109 N / A

E = (1.32 i^+ 3.56 j^) 109 N/C

7 0

4 years ago

true or false: as negative thundercloud passes over the city it drives electrons deep into the earth leaving a surface positive.

11Alexandr11 [23.1K]

The answer is m o s t defiantly false good man

3 0

3 years ago

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The capacitance of a capacitor depends on what?

bonufazy [111]

Answer:

The capacitance of a capacitor depends on the charge and voltage of a system. It is also dependent, if present, on the dielectric as well.

General Formulas and Concepts:
Gauss's Law

Capacitance Formula: $\displaystyle C = \frac{Q}{V}$

Q denotes charge
V denotes voltage

Dielectric Capacitance Formula: $\displaystyle C = \kappa C_0$

C₀ denotes original capacitance
κ denotes the dialectic constant

Explanation:

A capacitor stores charge when run through an electrical current. The capacitance is how much charge a capacitor can hold.

We can define the relationship of capacitance by using the formula. Capacitance is inversely proportional to the potential energy, or voltage, of the system. Therefore, you will need to know what the charge Q of the system as well has voltage V in order to find the capacitance.

If there is a dielectric involved inside the capacitance, you also must incorporate the value of the dielectric constant into your capacitance. A dielectric is directly proportional to the capacitance; the bigger the dielectric constant, the bigger capacitance, as denoted in our equation.

Topic: AP Physics C - EMAG

Unit: Gauss's Law

5 0

2 years ago