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Evgen [1.6K]
3 years ago
7

Nitrogen is used in many plant fertilizers. When it rains, the excess fertilizers run off into streams, rivers, and eventually a

re carried to the ocean. Algae in the water feed off of the nitrogen in the fertilizers. The excess nutrients can cause a huge mat of algae to grow, called an algal bloom.
When the nitrogen is all used up, the algae die and decomposing bacteria begin to consume them. The bacteria multiply and consume most of the oxygen in the water, causing many of the fish and other larger organisms in the water to suffocate and die.

How could the problem of algal blooms be solved?
A.
The government should start a program in which they clean out all the algae from the lakes and streams before they become a problem.
B.
Antibiotics should be added to the oceans to kill all of the bacteria before they can consume the dead algae.
C.
Farmers and gardeners should use other methods to provide crops with the nitrogen they need.
D.
Fish should be trained to swim to other parts of a body of water when the oxygen levels in one area become too low.
Physics
2 answers:
natita [175]3 years ago
4 0

Answer:

C. Farmers and gardeners should use other methods to provide crops with the nitrogen they need.

Explanation:

That was the right answer on study island :/

allsm [11]3 years ago
3 0

C. Farmers and gardeners should use other methods..........

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What can make a stronger electric or magnetic field?
rusak2 [61]

Answer:

add more coils

Explanation:

this increases the strength of the magnetic field

5 0
3 years ago
A lamp is connected to the power supply.
Vika [28.1K]

Answer:

There are 45 turns in the secondary coil.

Explanation:

Given that,

Input potential of the lamp, V_{in}=5\ V

The output potential of the lamp, V_{out}=1.5\ V

Number of turns in primary coil, N_P=150

We need to find the number of turns needed on the secondary coil. We know that the ratio for a transformer is as follows :

\dfrac{V_{out}}{V_{in}}=\dfrac{N_s}{N_P}\\\\N_s=\dfrac{V_{out}N_P}{V_{in}}\\\\N_s=\dfrac{1.5\times 150}{5}\\\\N_s=45\

So, there are 45 turns in the secondary coil.

5 0
3 years ago
Determine the total moment of inertia of a merry-go round with 5 children sitting on it. Of the five children, four are seated a
BaLLatris [955]

Answer:

Explanation:

Given that,

We have five children.

Each of mass m =30kg

They sit on a merry go round

Mass of Merry go round M= 150kg

Radius of Merry go round is r =2m

Four children sit at the edge of the merry go round but one child sit at the centre.

The four child that sit at the edge are 2m from the centre of the merry go round but the one at the centre is 0m from the centre

Moment of inertia?

Moment of inertia is given as

I=Σmi•ri²

For the question, the moment of inertia is the combination of inertial of child and the merry go round

I= I(merry go round) + I(four child)+ I(last child)

The merry go round is assumed to be a solid cylinder, so it is going to have the moment of inertia of solid cylinder

Then,

I(merry go round ) =½ Mr²

Also, Four of the child has the same moment of inertia, they are 2m form the centre of the merry go round why the last child has no moment of inertia

I= I(merry go round) + I(four child) +I(last child )

I= ½Mr² + 4mr² + mr'²

I = ½ × 150 ×2² + 4×30×2² + 30×0²

I = 300 +480+0

I = 780 kgm²

7 0
3 years ago
A 26.0 kg beam is attached to a wall with a hinge while its far end is supported by a cable such that the beam is horizontal. If
Nuetrik [128]

Answer:

Force exerted by the hinge on the beam = 109.24N

Explanation:

Weight = mg = 26 x 9.81 = 255.06 N

Vertical component = T sin θ

Horizontal component = Tcos θ

Now, there are 3 vertical forces acting on the beam. These are;

- The downward force which is the weight of the beam.

- The vertical components of the tension in the cable.

-The force that hinge exerts on the beam are the upward forces.

Hence, for the beam to remain horizontal, the sum of the upward forces must be equal to the weight of the beam.

For us to determine the vertical component of the tension in the cable, we will do a torque problem. Let the pivot point be at the hinge. Let’s assume that the length of the beam is L. The vertical component of the tension in the cable will produce clockwise torque while the weight of the beam will produce counter clockwise torque.

Tbus;

Clockwise torque = TL sin 61

Since the center of mass of beam is at the middle of the beam, the distance from the hinge to the weight of the beam is L/2.

Counter clockwise torque = WL/2

Thus;

TL sin 61 = WL/2

L will cancel out.

T sin 61 = 255.06/2

T x 0.8746 = 127.53

T = 127.53/0.8746 = 145.82 N

Now, the equation to determine the vertical component of the force that the hinge exerts on the beam is given as;

T + F = W

Thus;

145.82 + F = 255.06

F = 255.06 - 145.82 = 109.24 N

8 0
3 years ago
Calculate the force of gravity on a 1–kilogram box located at a point 1.3 × 107 meters from the center of Earth if the force on
Sati [7]

Since you already gave us the weight of the 2.5-kg box,
we don't even need to know what the distance is, just
as long as it doesn't change.

Look at the formula for the gravitational force:

                           F = G  m₁ m₂ / R² .

If 'G', 'm₁' (mass of the Earth), and 'R' (distance from the Earth's center)
don't change, then the Force is proportional to  m₂ ... mass of the box,
and you can write a simple proportion:

                       (6.1 N) / (2.5 kg)  =  (F) / (1 kg)

Cross-multiply:  (6.1 N) (1 kg)  =  (F) (2.5 kg)

Divide each side by (2.5 kg):  F = (6.1N) x (1 kg) / (2.5 kg)  =  2.44 N .

5 0
3 years ago
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