1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jarptica [38.1K]
3 years ago
10

A bat strikes a 0.145 kg baseball. Just before impact, the ball is traveling horizontally to the right at 40.0 m/s; when it leav

es the bat, the ball is traveling to the left at an angle of 30∘ above horizontal with a speed of 52.0 m/s. The ball and bat are in contact for 1.85 ms.

Physics
1 answer:
Furkat [3]3 years ago
7 0

Answer:

A bat strikes a 0.145 kg baseball. Just before impact, the ball is traveling horizontally to the right at 40.0 m/s; when it leaves the bat, the ball is traveling to the left at an angle of 30∘ above horizontal with a speed of 52.0 m/s. The ball and bat are in contact for 1.85 ms, find the horizontal and vertical components of the average force on the ball.

The average horizontal force is 389.18 N and vertical component of the average force is 3221.62 N.

Explanation:

Given:

Mass of the baseball, m = 0.145 kg

Velocity before the impact, v_1 = 40 m/s

Velocity after the impact, v_2 = 52 m/s

Angle of deflection, \theta = 30 deg

Time of contact, \triangle t = 1.85 ms

Conversion of milliseconds to seconds.

⇒ \triangle t = 1.85\times 10^-^3\ sec

Let the horizontal and vertical component of 'v1' and 'v2' be:

⇒ v_1x,v_1y,v_2x,v_2y

⇒ v_1x=40\ ms^-^1 and  v_2y= 0\ ms^-^1

⇒ Taking the vector components of 'v2'

⇒ v_2x=52cos(30) = 45.03\ ms^-^1 and v_2y=52sin(30)=40.97\ ms^-^1

We have to find the impulse in x-y, direction.

Momentum with 'v1'

⇒ P_1_x=mv_1_x

⇒ P_1_x=0.145(40)

⇒ P_1_x=0.145(40)

⇒ P_1_x=5.8\ kg.m.s^-^1  and P_1_y=0

Momentum with 'v2'

⇒ P_2_x=mv_2_x                       ⇒ P_2_y=mv_2_y

⇒ P_2_x=0.145(45.03)            ⇒ P_2_y=0.145(40.97)

⇒ P_2_x=6.52\ kg.m.s^-^1         ⇒ P_2_y=5.96\ kg.m.s^-^1

Now the difference in terms of impulse (J).

Horizontally                         Vertically

⇒ J_x=P_2_x-P_1_x                ⇒ J_y=P_2_y-P_1_y          

⇒ J_x=6.52-5.8                 ⇒ J_y=5.96-0

⇒ J_x=0.72\ kg.m.s^-^1          ⇒ J_y=5.96\ kg.m.s^-^1  

Now we know that Impulse is the product of  force and time.

So,

Horizontal force :                  Vertical force:

⇒  (F_x)_a_v_g=\frac{J_x}{\triangle t}                        ⇒ (F_y)_a_v_g=\frac{J_y}{\triangle t}

⇒ (F_x)_a_v_g=\frac{0.72\ kg.ms^-^1}{1.85\times 10^-^3\ s}           ⇒ (F_y)_a_v_g=\frac{5.96\ kg.m.s^-^1}{1.85\times 10^-^3\ s}

⇒ (F_x)_a_v_g=389.18\ N               ⇒ (F_x)_a_v_g=3221.62\ N

So the horizontal force is 389.18 N and vertical component of the average force is 3221.62 N.

You might be interested in
I just want to shift to another country to learn like London so who can tell me the progress​
scoray [572]

Answer:

by shift do you mean travel

Explanation:

3 0
3 years ago
The beat your doctor listens to through a sethoscope is the sound of the four values opening
djyliett [7]

and closing .

The heart has 4 valves. They are what makes the lub-dub lub-dub sounds that can be heard from the chest.  

The mitral valve is located between the left atrium and the left ventricle. It closes the left atrium to collect oxygenated blood from the lungs and opens to pass it on to the left ventricle.

The tricuspid valve is located between the right atrium and the right ventricle. It closes the right atrium to hold unoxygenated blood and opens to pass it on to the right ventricle ensuring a one way flow.

The aortic valve is located between the aorta and the left ventricle. It closes the left ventricle and opens to the aorta to pass on the oxygen-rich blood to the body.

The pulmonary valve is located between the pulmonary artery and the right ventricle. It closes off the right ventricle and opens to pass on unoxygenated blood to the lungs.


5 0
3 years ago
A ball of mass 5 kg attached to a string is swung in a horizontal circle of radius 0.5 m. If the tension in the string is 10 N,
kirill115 [55]

Answer:

0 J

Explanation:

given,

mass of the ball = 5 kg

radius of the horizontal circle = 0.5 m

tension in the string = 10 N

Work done = ?

Work done by the tension in the circular path will be equal to zero.

This is because body moves in circular path, the centripetal force act along the radius of the circle and motion is right angle to the tension on the string.

so, work done = F s cos θ

     θ = 90°,

work done = F s cos 90°        ∵ cos 90° = 0

Work done = 0 J

8 0
3 years ago
Part of a neutralization reaction between an acid and a base is shown below. What is the second product of the reaction?
icang [17]
Salt compound. it is a double displacement
8 0
3 years ago
Read 2 more answers
Suppose you take
kati45 [8]

Answer:

a current will be induced.

Explanation:

4 0
3 years ago
Read 2 more answers
Other questions:
  • What is the minimum thickness of coating which should be placed on a lens in order to minimize reflection of 566 nm light? The i
    10·1 answer
  • ______ attract objects made of iron ​
    13·1 answer
  • How can you find the net force if two forces act in opposite directions?
    13·1 answer
  • 27. Calculate the impulse when an average<br> force of 10 N acts on a cart for 5.0 s.
    12·1 answer
  • Find the current that flows in a silicon bar of 10-μm length having a 5-μm × 4-μm cross-section and having free-electron and hol
    11·1 answer
  • The mass of an object is measured on Earth. The mass is 5.0kg.The object is taken to the Moon. The mass of the object is measure
    14·1 answer
  • When a 15.00 kg mass is attached to a vertical spring, the spring is stretched 2.0 m such that the mass is 6.0 m above the table
    7·1 answer
  • I need written answer with solution:-
    7·1 answer
  • The first law of thermodynamics is just another form of the _____.
    13·1 answer
  • B. Write true or false for the following statements.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!