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Karo-lina-s [1.5K]
3 years ago
15

Scientist once believed that the structire of the universe had changed very little

Physics
1 answer:
Aloiza [94]3 years ago
4 0

The Universe is always expanding outwards

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What is the value of work done on an object when a
tino4ka555 [31]
W = F * s
Here, F = 50 N
s = 15 m

Substitute their values, 
W = 50 * 15
W = 750 J

In short, Your Answer would be 750 Joules

Hope this helps!
7 0
3 years ago
What type of nuclear decay releases energy but not a particle?
statuscvo [17]
I believe gamma decay but i may be wrong
7 0
3 years ago
Read 2 more answers
17. Suppose you were standing on a scale in an elevator in free fall. What would the scale read?
lianna [129]

17

What would the scale read? zero

18 In free fall you are being pulled by a gravity. "Truly" weightless presumably happens in deep space where there is nothing to pull you.

19 coasters accelerate down to simulate weight loss/zeroised. As do NASA planes,

Roller coasters are for fun seekers. NASA is for science

5 0
4 years ago
Read 2 more answers
An electromagnetic wave of intensity 150 W/m2 is incident normally on a rectangular black card with sides of 25 cm and 30 cm tha
LenKa [72]

Answer:

3.75 × 10⁻⁸ N

Explanation:

Given:

Intensity of the electromagnetic wave, I = 150 W/m²

Sides of the board = 25 cm (= 0.25 m) and 30 cm (= 0.30 m)

therefore,

the area of the rectangular box, A = 0.25 × 0.30 = 0.075 m²

Now,

force exerted on the card by the radiation, F = \frac{IA}{C}

here,

C is the speed of the light = 3 × 10⁸ m/s

on substituting the respective values, we get

F = \frac{150\times0.075}{3\times10^8}

or

F = 3.75 × 10⁻⁸ N

5 0
3 years ago
Calculate the change in length of concrete sidewalk (coefficient of linear expansion for concrete is 12*10^-6/celcius) that is 1
anyanavicka [17]

Answer:

The answer to your question is 5.4 cm

Explanation:

This problem refers to calculate the change in length in one dimension due to a change in temperature.

Data

α = 12 x 10⁻⁶

Lo = 150 meters

ΔT = 30 °C

Formula

                    ΔL/Lo = αΔT

solve for ΔL

                    ΔL = αLoΔT

Substitution

                    ΔL = (12 x 10⁻⁶)(150)(30)

Simplification

                    ΔL = 0054 m = 5.4 cm

7 0
3 years ago
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