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ella [17]
3 years ago
8

Can you explain so I can understand

Chemistry
2 answers:
lions [1.4K]3 years ago
7 0
So, it's asking which is not needed for an electric circuit
______________________________________________

In that case, think of or google a picture of an electric circuit diagram. 
_____________________________________________________

Look at one and think of something that would not be needed for an electric circuit [ Based on the answer choices ] 
__________________________________________________________

If you need the answer, comment that and I will tell you.
____________________________________________

Glad I could help, and good luck!
__________________________
__________________________
__________________________

Art [367]3 years ago
4 0
It would be insulator because an insulator kills electricity, it can't travel through it. 
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Acetonitrile major species present when dissolved in water
IrinaVladis [17]

Acetonitrile refers to the chemical compound exhibiting the formula CH₃CN. It is the basic organic nitrile and a colorless liquid. It is generated primarily as a byproduct of acrylonitrile production. It is used as a polar aprotic solvent in the purification of butadiene and in organic synthesis.  

The addition of water to cyanides generates amines and acids. Acetonitrile produces ammonia and acetic acid.  

CH₃CN (acetonitrile) → CH₃COOH (acetic acid) + NH₃ (ammonia)


3 0
3 years ago
A 3.452 g sample containing an unknown amount of a Ce(IV) salt is dissolved in 250.0-mL of 1 M H2SO4. A 25.00 mL aliquot is anal
SOVA2 [1]

Answer:

1,812 wt%

Explanation:

The reactions for this titration are:

2Ce⁴⁺ + 3I⁻ → 2Ce³⁺ + I₃⁻

I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻

The moles in the end point of S₂O₃⁻ are:

0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:

4,463x10⁻⁴ moles of S₂O₃⁻×\frac{1molI_{3}^-}{2molS_{2}O_{3}^-} = 2,2315x10⁻⁴ moles of I₃⁻

As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:

2,2315x10⁻⁴ moles of I₃⁻×\frac{2molCe^{4+}}{1molI_{3}^-} = 4,463x10⁻⁴ moles of Ce(IV). These moles are:

4,463x10⁻⁴ moles of Ce(IV)×\frac{140,116g}{1mol} = <em>0,0625 g of Ce(IV)</em>

As the sample has a 3,452g, the weight percent is:

0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>

I hope it helps!

5 0
3 years ago
What is the amount of moles for 12.0 g Ar?
Digiron [165]

if i am correct it shall be 12. because i am thinking, 1 mole = 1 ar.

8 0
3 years ago
Read 2 more answers
Which of the following is a major difference between elliptical galaxies and spiral galaxies?
SashulF [63]

Its A because I did it on connexus

5 0
3 years ago
Help me please.. dont understand
dedylja [7]
When gases get cooler the molecules slow down or lose energy and condense so the volume in the tire or soccer ball would decrease and may feel flatter
4 0
3 years ago
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