Answer:
The average power of the engine of the sports car is 56.32 kW
Explanation:
Given;
mass of the sports car, m = 1100 kg
initial velocity of the sports car, u = 0 m/s
final velocity of the sports car, v = 32 m/s
time of motion, t = 10 s
The kinetic energy of the car is given by;
K.E = ¹/₂m(v² - u²)
K.E = ¹/₂mv²
K.E = ¹/₂ x 1100 x 32²
K.E = 563200 J
The average power of the engine of the sports car is given by;
Pavg = Energy / time
Pavg = 563200 / 10
Pavg = 56320 W
Pavg = 56.32 kW
Therefore, the average power of the engine of the sports car is 56.32 kW
I think it's a) 1st Newton's law... so sorry if it's wrong...
Answer:
H = 54.37
Explanation:
given,
lead ball attached at = 1.70 m
rate of revolution = 3 revolution/sec
height above the ground = 2 m
circumference of the circle = 2 π r
= 2 x π x 1.7
= 10.68 m
v = 32.04 m/s
using conservation of energy
H = 54.37
the maximum height reached by the ball is equal to H = 54.37
It is possible for on object to be going at 100 miles per hour, but still have a velocity. This is because the object going at 100 miles per hour has speed, which is a scalar quantity, which is defined by only magnitude, but the velocity of the object can be 0, since velocity is a vector quantity which is defined by both magnitude and direction.
Since this object only has magnitude and no direction (which is not given), then the velocity can be 0
