From the calcuation, the percent ionic character of the bond is 70%
<h3>What is percent ionic character?</h3>
The term percent ionic character has to do with the degree of ionic bonding that is contained in a compound. It can be estimated from the electronegativity of each element.
We can use the formula; 100(1 - e^(-ΔEN² / 4))
EN = χB − χA * 100/1
EN = 3.5 - 1.5 = 1
100(1 - e^(-1)^2/4)
= 70%
Learn more about percent ionic character:brainly.com/question/7034446
#SPJ1
In order to obtain the empirical formula, first divide each
element by its molar mass which can be found in the periodic table. The answer
in the first step would be the number of moles of each element. Then divide
each element with the lowest number of moles obtained in the first step in this
case Phosphorus had the lowest number of moles. Then round it up to the nearest
whole number. The empirical formula then is Phosphorus pentafluoride or PF5.
This is due to the phenomenon known as the Inert pair effect.
Orbitals shield better with a lower azimuthal quantum number(l). Hence, s orbitals shield better than p which shields better than d which is better than f, etc.
The electronic configuration of Si is [Ne] 3s²3p². The 2s and 2p orbitals are shielding the electrons from the nucleus. So the s and p electrons are ready to be ionized. And hence shows a +4 oxidation state.
Similarly, as we move down the group, atomic size increases, and metallic character also increases. Also, lead is below Si and a lower oxidation state is more stable down the group. Hence lead shows a +2 oxidation state.
To learn more about the oxidation state, visit: brainly.com/question/11313964
#SPJ4
C. 14
you would subtract the mass number from the protons or the atomic number because in order to find the mass number you would add the protons and neutrons :)
Represent <span>the coefficients of the balanced reaction.
hope this helps!</span>
