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Delicious77 [7]

3 years ago

5

Marisa’s car accelerates at an average rate of 2.6m/s^2. Calculate how long it takes her car to accelerate from 24.6m/s to 26.8m

/s? Show your work.

1 answer:

djverab [1.8K]3 years ago

8 0

given info is... Acceleration(a)=2.6m/s^2

final velocity(v)=26.8m/s

initial velocity(u)=24.6m/s

need to find.... time(t)=?

$a=\frac{v-u}{t} \\2.6=\frac{26.8-24.6}{t} \\\\$

$t=\frac{v-u}{a}$

$t=\frac{26.8-24.6}{2.6}$

$t=0.846s$

Explanation:

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Se tienen 500g de alcohol etílico a una temperatura de -40 °C ¿Cuánto calor se necesita para transformarlo a vapor a una tempera

Feliz [49]

The question is: You have 500g of ethyl alcohol at a temperature of -40 ° C. How much heat is needed to transform it into steam at a temperature of 150ºC?

Answer: 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of $-40^{o}C$ to $150^{o}C$ .

Explanation:

Given: Mass = 500 g

Initial temperature = $-40^{o}C$

Final temperature = $150^{o}C$

The standard value of specific heat of ethyl alcohol is $2.46 J/g ^{o}C$ .

Formula used to calculate the heat energy is as follows.

$q = m \times C \times (T_{2} - T_{1})$

where,

q = heat energy

m = mass of substance

C = specific heat

$T_{1}$ = initial temperature

$T_{2}$ = final temperature

Substitute the values into above formula as follows.

$q = m \times C \times (T_{2} - T_{1})\\= 500 g \times 2.46 J/g^{o}C \times [150 - (-40)]^{o}C\\= 233700 J$

Thus, we can conclude that 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of $-40^{o}C$ to $150^{o}C$ .

8 0

3 years ago

A satellite is acted upon by a 10n force upwards and 20n force downwards. What is the net force acting on the satellite and what

Lina20 [59]

Answer:

Net force = 10 N in downward direction

Explanation:

Given that,

Upward force = 10 N

Downward force = 20 N

Let downward is negative and upward is positive.

Net force = 10+(-20)

= -10 N

So, the net force is 20 N and it is acting in downward direction.

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3 years ago

Please help!!!! I will give brainliest if correct!!!

scZoUnD [109]

Answer:

The density ρ of metal block is 8.92g/cm³

So from the given density table this corresponds to copper which has density of 8.92(g/mL)

Explanation:

Oh yeah, I got the correct unit update,

Now this problem bothers on the density of substances

We know that the density of a substance is expressed as

Density ρ= mass/ volume

Given data

Mass of metal block m= 62.44g

Volume of metal block v= 7 cm³

Hence we can find the density of the metal block by plugging in our data into the expression for density

ρ of metal block = 62.44/7

ρ of metal block = 8.92g/cm³

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4 0

3 years ago

A plane starting at rest at one end of a runway undergoes a uniform acceleration of 4.8 m/s

yKpoI14uk [10]

initial velocity=0m/s=u
Acceleration=a=4.8m/s^2
Time=t=15s

Final velocity be v

$\\ \sf\longmapsto v=u+at$

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8 0

2 years ago

A 0.5 μF and a 11 μF capacitors are connected in series. Then the pair are connected in parallel with a 1.5 μF capacitor. What i

NISA [10]

Answer:

$C_{eq}=1.97\ \mu F$

Explanation:

Given that,

Capacitance 1, $C_1=0.5\ \mu F$

Capacitance 2, $C_2=11\ \mu F$

Capacitance 3, $C_3=1.5\ \mu F$

C₁ and C₂ are connected in series. Their equivalent is given by :

$\dfrac{1}{C'}=\dfrac{1}{C_1}+\dfrac{1}{C_2}$

$\dfrac{1}{C'}=\dfrac{1}{0.5}+\dfrac{1}{11}$

$C'=0.47\ \mu F$

Now C' and C₃ are connected in parallel. So, the final equivalent capacitance is given by :

$C_{eq}=C'+C_3$

$C_{eq}=0.47+1.5$

$C_{eq}=1.97\ \mu F$

So, the equivalent capacitance of the combination is 1.97 micro farad. Hence, this is the required solution.

3 0

2 years ago