Answer:
B
Explanation:
there are three modes of heat transfer which are
- conduction
- convection
- radiation
Conduction is a mode of heat transfer in solid materials
Convection refers to a mode of heat transfer of fluids in motion.
Radiation occurs when heat moves as energy waves in form of infrared radiation. The energy from the sun reaches us by radiation.
From the list of options;
option A refers prevention of heat transfer by radiation
option B refers to noodles rising and falling in a poy of boiling water. The path which the noodles move shows the convective path of the fluid.
option C refers to heat transfer by conduction
Option D refers to oth convection and radiation as modes of heat transfer.
option B best describes heat transfer by convection
Explanation:
Since, ∆ = − 0, we can find what temperature is required to cause the volume to be 0.15% larger than it is at 20℃: = 0 + ∆ = 20℃ + 29.4℃ = 49.4℃. Answer: = 49.4℃.
Answer:
226.6 N
Explanation:
The work done by the push is given by:
where
p is the magnitude of the push
d is the displacement of the crate
is the angle between the direction of the push and the displacement of the crate
On the contrary, the work done by the frictional force is:
where
is the frictional force, with m=1.00x102 kg being the mass of the crate ang g=9.81 m/s^2 the gravitational acceleration
d is the displacement of the crate
the negative sign is due to the fact that the frictional force acts in the opposite direction to the displacement of the crate.
The net work must be zero, so:
Substituting the previous equations into this one, we find:
which we can solve to find p:
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Answer:
Explanation:
It is given that,
Speed of one quoll around a curve, v = 3.2 m/s (maximum speed)
Radius of the curve, r = 1.4 m
On the curve, the centripetal force is balanced by the frictional force such that the coefficient of frictional is given by :
So, the coefficient of static friction between the quoll's feet and the ground in this trial is 0.74. Hence, this is the required solution.