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Natalka [10]
3 years ago
9

Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl

ock is pulled with a force of 100 N. What is the tension in the string connecting block 100 to block 99? What is the tension in the string connecting block 50 to block 51?
Physics
1 answer:
Ivanshal [37]3 years ago
4 0

Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

F=ma

100=100m\times a

ma=1\ N

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

F_{100-99}=ma

F_{100-99}=1

We need to calculate the total number of masses attached to the string

Using formula for mass

m'=(100-50)m

m'=50m

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

F_{50}=m'a

Put the value into the formula

F_{50}=50m\times a

F_{50}=50\times1

F_{50}=50\ N

Hence, The tension in the string connecting block 50 to block 51 is 50 N.

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Explanation:

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2 ) Force on m₁ accelerating it , which is nothing but friction force on it by m₂

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The same force will be applied by m₁ on m₂ as friction force which will act in opposite direction.

3 ) Maximum friction force that is possible between m₁ and m₂

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= 193.55 N

Acceleration of m₁

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This is the common acceleration in case of maximum tension required

So tension in rope

= ( 25 +91 ) x 7.742

= 898 N

4 ) In case of upper crate sliding on m₂ , maximum friction force on m₁

=  μ_k m₁g

= .62 x 25 x 9.8

= 151.9 N

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Heat always flows from a _________ object to a __________ one.
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Heat always flows from a B. hotter object to a colder one.

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Leash a block of 0.5 kg down the entire length of an inclined plane forming a name of 37 ° with the horizontal. Friction with th
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The potential energy of the block is given by:
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The potential energy of a spring is given by:
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k spring constant
x compression of the spring

If the block starts from rest it has potential energy, but no kinetic energy. As it slides down the incline potential energy is converted into kinetic energy. When the block hits the spring the kinetic energy is converted into spring's potential energy. If the spring is fully compressed and the block is at rest again, the block has transferred all its energy into the spring. No energy is lost. So we can write:

m * g * h = 0.5 * k * x²

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A gas expands and does PV work on its surroundings equal to 319 J. At the same time, it absorbs 136 J of heat from the surroundi
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Answer:

The change in energy of the gas during the process is -1.83\times 10^{2} joules.

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W_{out} - Work done by the gas, measured in joules.

\Delta E - Change in energy, measured in joules.

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