Complete Question
The speed of a transverse wave on a string of length L and mass m under T is given by the formula
If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
Answer:
Explanation:
From the question we are told that
Speed of a transverse wave given by
Maximum Tension is 
Generally making 
subject from the equation mathematically we have
Therefore the Linear mass in terms of Velocity is given by
answer
option d is the correct answer
explanation
as we know frequency is equal to 1 /t
f= 457 Hz
t=1
SO, 1/457
=0.0022sev
Answer:
4
Explanation:
It has 8 O atoms and 4 O2(g) molecules
Answer: 0.01 m
Explanation: The formulae for capillarity rise or fall is given below as
h = (2T×cosθ)/rpg
Where θ = angle mercury made with glass = 50°
T = surface tension = 0.51 N/m
g = acceleration due gravity = 9.8 m/s²
r = radius of tube = 0.5mm = 0.0005m
p = density of mercury.
h = height of rise or fall
From the question, specific gravity of density = 13.3
Where specific gravity = density of mercury/ density of water, where density of water = 1000 kg/m³
Hence density of mercury = 13.3×1000 = 13,300 kg/m³.
By substituting parameters, we have that
h = 2×0.51×cos 50/0.0005×9.8×13,300
h = 0.6556/65.17
h = 0.01 m
Answer:
The block's mass should be 
Explanation:
Given:
Cart with mass 
From the conservation of energy before mass is added,
Where 
amplitude of spring mass system, 
spring constant
Now new mass 
is added to the system,
Here, given in question frequency is reduced to half so we can write,
Where 
frequency of system before mass is added, 
frequency of system after mass is added.
Therefore, the block's mass should be
