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4 years ago

Which molecule has the same shape and hybridization as methane

Chemistry

1 answer:

Korvikt [17]4 years ago

6 0

Hi, the answer is <span>CF2Cl2 :)</span>

You might be interested in

Predict the whether the following reactions are possible or not.

vova2212 [387]

Answer:

1. No

2. No

3. Yes

4. No

5. Yes

6. No

Explanation:

Use the reactivity series. If the element is above it, it is more reactive. More reactive elements can displace less reactive elements from their compounds.

5 0

3 years ago

Determine the number of grams of C4H10 that are required to completely react to produce 8.70 mol of CO2 according to the followi

Nitella [24]

Answer:

126.4 g of $C_{4}H_{10}$ are required

Explanation:

Balanced reaction: $2C_{4}H_{10}+13O_{2}\rightarrow 8CO_{2}+10H_{2}O$

According to balanced reaction-

8 moles of $CO_{2}$ are produced from 2 moles of $C_{4}H_{10}$

So, 8.70 moles of $CO_{2}$ are produced from $(\frac{2}{8}\times 8.70)$ moles of $C_{4}H_{10}$ or 2.175 moles of $C_{4}H_{10}$

Molar mass of $C_{4}H_{10}$ = 58.12 g/mol

So, mass of $C_{4}H_{10}$ required = $(2.175\times 58.12)g$ = 126.4 g

Hence 126.4 g of $C_{4}H_{10}$ are required

5 0

3 years ago

If density usually increases with decreasing temperature, why does ice float on liquid water? Explain.

zepelin [54]

Answer:

If you continue to cool water past 4 degrees Celsius, its density starts to plummet (you can see this in the graph). At zero degrees, i.e., the temperature at which water turns into ice, the density of water is actually quite low. It turns out that ice has a lower density than water, and any object that has a lower density than the liquid form on which it’s kept (in this case, water) will be able to float!

Explanation:

6 0

3 years ago

When a 4.2 gram sample of mercury (Il) oxide, HgO is decomposed into its elements by •

Usimov [2.4K]

Hg = (3.2 : 4.2) x 100% = 76.19%

O = (1 : 4.2) x 100% = 23.81%

7 0

2 years ago

How much faster will ammonia vapor travel across a room then carbon dioxide

FromTheMoon [43]

Answer:

D) 1.61 times faster

Explanation:

$vrms_{NH3}$ = √(3)RTM

R constant= 0.08206

T=constant, so in this problem we dont need a value for it

M=17.031 g/mol

√(3)(0.08206)(17.031)= 2.047

$vrms_{CO2}$ = √(3)RTM

R constant= 0.08206

T=constant, so in this problem we dont need a value for it

M= 44.01 g/mol

√(3)(0.08206)(44.01)= 3.29

Since we are trying to measure how much faster NH3 will be, we have to realize that mass and speed have an inverse relationship.

So instead of doing (2.047)/(3.29) = 6.22

we have to flip the values to get (3.29)/(2.047)= 1.61

6 0

3 years ago