1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nika2105 [10]
3 years ago
7

Given that an activity's normal time and cost are 10 days and $400, respectively, and its crash time and cost are 5 days and $80

0, respectively, what is the activity's slope?
Chemistry
2 answers:
aleksley [76]3 years ago
4 0
(800 - 400) / ( 5 - 10 )
= -80
pantera1 [17]3 years ago
3 0

Answer:

The slope of the activity is 80

Explanation:

To find maximum crashing time= normal time - crashing time= 10-5=5

Slope of activity=800-400/5= 80

You might be interested in
Drinking energy drinks makes people more aggressive.
ch4aika [34]
Outcome (dependent) variable-drinking energy drinks

Test (independent) variable- more aggressive
7 0
2 years ago
If a car can go from 0 to 60 mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50
tangare [24]

Answer:

87.5 mi/hr

Explanation:

Because a = Δv / Δt (a = vf - vi/ Δt), we need to find the acceleration first to know the change in velocity so we can determine the final velocity.

vf = 60 mi/hr

vi = 0 mi/hr

Δt = 8 secs

a = vf - vi/ Δt

= 60 mi/hr - 0 mi/hr/ 8 secs

= 60 mi/hr / 8 secs

= 7.5 mi/hr^2

Now that we know the acceleration of the car is 7. 5 mi/hr^2, we can substitute it in the acceleration formula to find the final velocity when the initial velocity is 50 mi/hr after 5 secs.

vi = 50 mi/ hr

Δt = 5 secs

a = 7.5 mi/ hr^2

a = vf - vi/ Δt

7.5 = vf - 50 mi/hr / 5 secs

37.5 = vf - 50

87.5 mi/ hr = vf

7 0
3 years ago
Why do you need to use soap when you wash oil from your hands
yawa3891 [41]

Answer:

Germs stick to the oil on your hands, and washing with just water doesn't work because oil and water don't mix, but soap dislodges the germs and oil from your hands

Explanation:

3 0
3 years ago
Read 2 more answers
For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

6 0
3 years ago
What is the mass of 0.60 moles of Al
KIM [24]

16 g. The mass of 0.60 mol Al is 16 g.

Molar mass of Al = 26.98 g/mol

Mass of Al = 0.60 mol Al x (26.98 g Al/1 mol Al) = 16 g Al

6 0
3 years ago
Read 2 more answers
Other questions:
  • Assume that each tablet's mass was 1,000 mg, and remember that you used 0,200 L of water each time,
    12·2 answers
  • I don’t know it A is correct please tell me the right answer
    5·2 answers
  • 5 example of dilute solution
    14·2 answers
  • The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abb
    5·1 answer
  • Why does a catalyst work for a long time before it needs replacing?
    7·1 answer
  • Write the equation for the decay of kr-85
    11·2 answers
  • What is displacement reaction?​
    5·1 answer
  • How many moles of O2 are needed to make 1.98 moles of SO3
    11·1 answer
  • What can you say about an atom with 4 protons, 2 neutrons, and 5 electrons?
    5·1 answer
  • Chemical Reactions
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!