Ask question

Ask question

All categories

professor190 [17]

4 years ago

9

6. What is a polyatomic ion? (You should also memorize the name, formula, and charge of the polyatomic ions listed in the lectur

e materials)

1 answer:

strojnjashka [21]4 years ago

6 0

A polyatomic ion is a group of elements that has a charge that is not 0. for example the charge of P04 is -3

You might be interested in

A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,

Scorpion4ik [409]

<u>Answer:</u> The value of $K_c$ is coming out to be 0.412

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For $Sb_2S_3$ </u>

Given mass of $Sb_2S_3$ = 1.00 kg = 1000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of $Sb_2S_3$ = 339.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol$

<u>For hydrogen gas:</u>

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol$

<u>For hydrogen sulfide:</u>

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol$

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

$Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)$

Initial: 2.944 5

At eqllm: 2.944-x 5-3x 2x 3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

$\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712$

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$

The expression of $K_c$ for above equation, we get:

$K_c=\frac{[H_2S]^3}{[H_2]^3}$

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

$K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412$

Hence, the value of $K_c$ is coming out to be 0.412

3 0

3 years ago

Which of the following would a chemist be most likely to study?

qaws [65]

B. because the other options are different sciences (biology and entomology)

5 0

3 years ago

How many grams of carbon are present in 45.0 g of CCl4?

lisabon 2012 [21]

To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:

45.0 g CCl4 ( 1 mol CCl4 / 153.82 g CCl4 ) ( 1 mol C / 1 mol CCl4 ) ( 12.01 g C / 1 mol C ) = 3.5135 g carbon present

Hope this answers the question. Have a nice day.

5 0

4 years ago

A solution of H2SO4 with a molal concentration of 5.25m has a density of 1.266 g/ml. what is the molar concentration of this sol

Gelneren [198K]

So first find the moles of the H₂SO₄: Mass = Moles x RFM
so mass = 5.25 x 98 = 514.5g of <span>H₂SO₄</span>

so to find how many Liters of solution use:

Volume = Density x Grams of solute (per kg +1000)

density = 1.266 x 514.5 +1000 = 1917.357kg/l

now use equation: Conc. = Moles / Volume of solution to find the conc.
Conc. = 5.25 x 1917.357 = 4.39Mol⁻¹
Hope that helps

6 0

3 years ago

Read 2 more answers

How can you simulate the radioactive half-life of an element?

ch4aika [34]

Answer:

TRIAL 1:

For “Event 0”, put 100 pennies in a large plastic or cardboard container.

For “Event 1”, shake the container 10 times. This represents a radioactive decay event.

Open the lid. Remove all the pennies that have turned up tails. Record the number removed.

Record the number of radioactive pennies remaining.

For “Event 2”, replace the lid and repeat steps 2 to 4.

Repeat for Events 3, 4, 5 … until no pennies remain in the container.

TRIAL 2:

Repeat Trial 1, starting anew with 100 pennies.

Calculate for each event the average number of radioactive pennies that remain after shaking.

Plot the average number of radioactive pennies after shaking vs. the Event Number. Start with Event 0, when all the pennies are radioactive. Estimate the half-life — the number of events required for half of the pennies to decay.

Explanation:

6 0

3 years ago