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Marat540 [252]
3 years ago
9

Please help me

Physics
1 answer:
katrin2010 [14]3 years ago
8 0

The pitch of a sound is determined by its wavelength and speed together, or its SPEED alone.

Helped?

Brainliest?

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Assuming that Albertine's mass is 60.0 kg , for what value of μk, the coefficient of kinetic friction between the chair and the
makvit [3.9K]

Answer:

\mu_k=0.101

Explanation:

It is given that,

Mass of Albertine, m = 60 kg

It can be assumed, the spring constant of the spring, k = 95 N/m

Compression in the spring, x = 5 m

A glass sits 19.8 m from her outstretched foot, h = 19.8 m

When she just reach the glass without knocking it over, a force of friction will also act on it. Using the conservation of energy for the spring mass system such that,

\dfrac{1}{2}kx^2=\mu_k mgh

\mu_k=\dfrac{kx^2}{2mgh}

\mu_k=\dfrac{95\times (5)^2}{2\times 60\times 9.8\times 19.8}

\mu_k=0.101

So, the coefficient of kinetic friction between the chair and the waxed floor is 0.101. Hence, this is the required solution.

3 0
3 years ago
An astronaut is doing repairs on the international Space Station. She throws a hammer into space with a velocity of 3m/s. How mu
Rainbow [258]

Answer:

The force is 15N

Explanation:

The formula is Force= mass × velocity.

From the question mass is 5kg, velocity is 3m/s.

F= 5×3

F= 15Newton.

Therefore the force is 15N.

3 0
3 years ago
Read 2 more answers
this stationary wave is what we call the first harmonic of the first normal mode of the system. in units of l, the length of the
pentagon [3]

First harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.

<h3>First harmonic of a closed pipe</h3>

The first harmonic of a closed pipe is the fundamental frequency of the closed of the closed pipe.

L = λ/4

where;

  • L is the length of the pipe
  • λ is the wavelength of sound

λ = 4L

But, v = F₀λ

v = F₀(4L)

F₀ = v/4L

where;

  • F₀ is the first harmonic
  • v is speed of sound

Thus, first harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.

Learn more about fundamental frequency here:  brainly.com/question/1967686

#SPJ11

<h3 />
6 0
1 year ago
Determine the torque applied to the shaft of a car that transmits 225 hp
Arisa [49]

Incomplete question.The complete question is here

Determine the torque applied to the shaft of a car that transmits 225 hp and rotates at a rate of 3000 rpm.

Answer:

Torque=0.51 Btu

Explanation:

Given Data

Power=225 hp

Revolutions =3000 rpm

To find

T( torque )=?

Solution

As

T(Torque)=\frac{W(Work)}{2\pi n(Revolutions) }

As force moves an object through a distance, work is done on the object. Likewise, when a torque rotates an object through an angle, work is done.

So

T=\frac{225*42.207}{2\pi 3000}\\ T=0.51 Btu

8 0
3 years ago
A car travels 20km West and then 20 km South. What is the magnitude of it's displacement vector
Ludmilka [50]

c. 28.km
11. Cartesian Coordinates.
X Y
S -3.5 4.5
T 0 -6.5
U 3.5 -2.5
what is angle of resultant vector STU measuring from positive x axis.
24 degrees below x

12. Cartesian Coordinates
Cartesian Coordinates.
X Y
S -3.5 4.5
T 0 -6.5
U 3.5 -2.5
what is magnitude of resultant vector STU
a. 4.9 b. 24 c. 16. d. 18
Seems right option is not there. The right one will be 7./2 ie 9.9
6 0
3 years ago
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