All categories

4 years ago

Which substance in the table below has the strongest intermolecular forces

Chemistry

2 answers:

nasty-shy [4]4 years ago

8 0

The strongest intermolecular bonding is hydrogen bonding. The hydrogen bonding is the electrostatic bonding between hydrogen atom and any of the electronegative atoms, such as Oxygen, Nitrogen and Flourine. The strength of H-F bonding is strongest, then H-N and then H-O bond.

tatiyna4 years ago

7 0

Answer : Option A) HF.

Explanation : Assuming the complete question as per the attachment.

H-F bonds are formed because of hydrogen bonding between H atom and F atom and is considered to be strongest amongst the rest other options given.

As given in the table it is clear that the molar mass of HF molecule is the lowest. It shows that, when dispersion increases in the molecule molecular weight also increases.

You might be interested in

PLEASE HELP!!!

ladessa [460]

Answer:

the answer is c. [.4r]3d104324p

7 0

3 years ago

What is the independent variable?<br> (For science)

DiKsa [7]

Answer:

The independent variable is what you change in the experiment.

Explanation:

The independent determines the dependent variable.

6 0

3 years ago

Calculate the pH of a solution whose H3O+ concentration is 2.1 x 10-3 M. Is the solution acidc, basic, or neutral?

Leona [35]

Answer:

Option A, The pH of the solution is 2.7 and the solution is acidic

Explanation:

As we know,

pH = - log [H3O+]

Substituting the given values, we get

pH = - log [2.1 x 10-3 M]

pH = - (-2.678)

pH = 2.678 or 2.7

The solution is acidic as pH value is less than 7

Hence, option A is correct

5 0

3 years ago

Mass = 25g, Volume = 5mL. What is the density? *

Fantom [35]

Answer:

5ml

Explanation:

m/v

25/5=5

means 25÷5=5

6 0

4 years ago

Iron fluoride (FeF2) dissociates according to the following equation:

melomori [17]

Answer:

S = 0.788 g/L

Explanation:

The solubility product (Kps) is an equilibrium solubization constant, which can be calculated by the equation:

$Kps = \frac{[product]^x}{[reagent]^y}$

Where x and y are the stoichiometric coefficients of the product and the reagent, respectively. Because of the aggregation form, the concentration of solids is always equal to 1 for use in this equation.

Analyzing the equation, we see that for 1 mol of $Fe^{+2}$ is necessary 2 mols of $F^-$ , so if we call "x" the molar concentration of $Fe^2$ , for $F^-$ we will have 2x, so:

$Kps = [Fe^{+2}].[F^-]^2\\\\2.36x10^{-6} = x(2x)^2\\\\2.36x10^{-6} = 4x^3\\\\x^3 = 5.9x10^{-7}\\\\x = \sqrt[3]{5.9x10^{-7}} \\\\x = 8.4x10^{-3} mol/L$

So, to calculate the solubility (S) of FeF2, which is in g/L, we multiply this concentration by the molar mass of FeF2, which is:

Fe = 55.8 g/mol

F = 19 g/mol

FeF2 = Fe + 2xF = 55.8 + 2x19 = 93.8 g/mol

So,

[tex]S = 8.4x10^{-3}x93.8

S = 0.788 g/L

4 0

4 years ago