If its asking the distance for the 65 db then use a proportion, if otherwise pleas clarify. It sounds like a pretty juicy conversation.
Answer:
Construct a quadrilateral ABCD, where
Construct a quadrilateral ABCD, whereAB = 4 cm, BC = 5 cm, CD = 6.5 cm and angle B = 105° and angle C = 80°
Based on the length of the Ethernet cable and the mass, the tension in the cable can be found to be 80 N.
<h3>How much tension is in the cable?</h3>
The tension in the cable can be found as:
= 4 x mass x length x frequency
Solving for the frequency is:
= 1 / (0.800 / 4)
= 1 / 0.20
= 5.0 Hz
The tension is therefore:
= 4 x 0.20 x 4.00 x 5
= 80N
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