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3 years ago

What are the conditions necessary for a terrestrial planet to have a strong magnetic field?.

Physics

1 answer:

Stells [14]3 years ago

6 0

Both a molten metallic core and reasonably fast rotation.

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The moon affects the tides by causing high and low tides.

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4 years ago

Communication with submerged submarines via radio waves is difficult because seawater is conductive and absorbs electromagnetic

REY [17]

Answer:

$\lambda=4000\ km$

Explanation:

It is given that,

Frequency for submarine communications, f = 76 Hz

We need to find the wavelength of those extremely low-frequency waves. the relation between the wavelength and the frequency is given by :

$c=f\times \lambda$

$\lambda=\dfrac{c}{f}$

$\lambda=\dfrac{3\times 10^8\ m/s}{76\ Hz}$

$\lambda=3947368.42\ m$

$\lambda=3947\ km$

$\lambda=4000\ km$

So, the wavelength of those extremely low-frequency waves is 4000 km. Hence, this is the required solution.

4 0

3 years ago

Write equations for both the electric and magnetic fields for an electromagnetic wave in the red part of the visible spectrum th

NeTakaya

Answer:

Explanation:

General equation of the electromagnetic wave:

$E(x, t)= E_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]$

where

$\phi =$ Phase angle, 0

c = speed of the electromagnetic wave, 3 × 10⁸

$\lambda =$ wavelength of electromagnetic wave, 698 × 10⁻⁹m

E₀ = 3.5V/m

Electric field equation

$E(x, t)= 3.5sin[\frac{2\pi}{6.98\times10^{-7}}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6x-2.7\times 10^{15}t)]$

Magnetic field Equation

$B(x, t)= B_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]$

Where B₀= E₀/c

$B_0 = \frac{E_0}{c} = \frac{3.5}{3\times10^8}=1.2 \times 10^{-8}T$

$B(x, t)= 1.2\times10^{-8}sin[\frac{2\pi}{6.98\times10^{-7}}(x-3\times 10^8t)]\\\\B(x, t)= 1.2\times10^{-8}sin[{9 \times 10^6}(x-3\times 10^8t)]\\\\B(x, t)= 1.2\times10^{-8}sin[{9 \times 10^6x-2.7\times 10^{15}t)]$