answer is A -e described electrons in specific orbits around the nucleus.
Answer:
96 g
Explanation:
Tomando en cuenta que estamos hablando de una solución de Nitrato de potasio cuya concentración es 12% m/V, debemos entonces usar la expresión de %m/V:
%m/V = msto / Vsol * 100 (1)
De esta expresión, debemos despejar la masa de soluto (msto) que es precisamente el valor que estamos buscando. Al hacer el despeje tenemos:
msto = %m/V * Vsol / 100 (2)
Ahora solo nos queda sustituir los valores dados y resolver:
msto = 12 * 800 / 100
<h2>
msto = 96 g de KNO₃</h2>
Espero te sirva.
ِAnswer:
1- The molarity of HCOOH = 9.515 M.
2- The mole fraction of HCOOH = 0.18.
Explanation:
<em>1- The molarity of HCOOH:</em>
- We can calculate the molarity of HCOOH using the relation:
M = (10pd)/molar mass.
p is the percent by mass of HCOOH = 35.9 %.
d is the specific gravity of HCOOH = 1.22 g/cm³.
Molar mass of HCOOH = 46.03 g/mol.
∴ M = (10pd)/molar mass = (10)(35.9 %)(1.22 gcm³) / (46.03 g/mol) = 9.515 M.
<em>2- The mole fraction of HCOOH:</em>
- We can suppose that we have a 100 g solution, that contains 35.9 g of HCOOH and 64.1 g of water.
<em>The mole fraction of HCOOH = (no. of moles of HCOOH) / (no. of moles of HCOOH + no, of moles of water).</em>
no. of moles of HCOOH = mass / molar mass = (35.9 g)/(46.03 g/mol) = 0.78 mol.
no. of moles of water = mass / molar mass = (64.1 g)/(18.0 g/mol) = 3.56 mol.
- The mole fraction of HCOOH = (no. of moles of HCOOH) / (no. of moles of HCOOH + no, of moles of water) = (0.78 mol) / (0.78 mol + 3.56 mol) = 0.18.
Answer:
True
Explanation:
No, a single particle cannot have a temperature at all, because temperature is a property of a large number of particles.- this is not my own words the website I got it from is https://www.quora.com/Can-a-single-particle-have-any-temperature
Answer:
The answer to the question is
Chlorine Cl₂
Explanation:
Graham's Law of effusion states that the rate of effusion of a gas is inversely proportional to the square root of the molar mass
0.238 = 
Therefore M₁ = 4÷0.238² = 70.61
Hence the mass of the gas is 70.61, that is X₂ = 70.61 or the molar mass of the element X = 70.61÷2 = 35.308 ≅35.453 Hence the gas is chlorine Cl₂
