30 mL. The two compounds need to balance each other out.
Answer:
O flower shape
Explanation:
Bats are just as important for pollination as insects and just like insects, plants use artifices to attract bats to their flowers, allowing them to have access to the pollen that will be taken elsewhere.
Bats are mainly attracted by the color and smell of flowers, the size and shape also play a role in attracting these animals, but the shape is less influential.
Answer:
Problem: The density of ethanol is 0.789 g/cm3 .What is its density in pounds per cubic inch ( lb/in3)?. Based on our data, ... 1 in = 2.54 cm. density = 0 . 789 g ...
Explanation:
Answer:

Explanation:
The metabolic pathway by which energy can be obtained from a fatty acid is called <u>"beta-oxidation"</u>. In this route, acetyl-Coa is produced by removing <u>2 carbons</u> from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the <u>number of rounds</u> that will take place for an <u>18-carbon fatty</u> acid using the following equation:

Where "n" is the <u>number of carbons</u>, in this case "18", so:

We also have to calculate the amount of Acetyl-Coa produced:

Now, we have to keep in mind that in each round in the beta-oxidation we will have the <u>production of 1
and 1
</u>. So, if we have 8 rounds we will have 8
and 8
.
Finally, for the total calculation of ATP. We have to remember the <u>yield for each compound</u>:
-)
-) 
-) 
Now we can do the total calculation:

We have to <u>subtract</u> "2 ATP" molecules that correspond to the <u>activation</u> of the fatty acid, so:

In total, we will have 128 ATP.
I hope it helps!
Answer:

Explanation:
Given that:
Half life = 30 min
Where, k is rate constant
So,
The rate constant, k = 0.0231 min⁻¹
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given that:
The rate constant, k = 0.0231 min⁻¹
Initial concentration
= 7.50 mg
Final concentration
= 0.25 mg
Time = ?
Applying in the above equation, we get that:-
