Energy= 2381 joules
heat= Mass(kg) *change in temperature(K) * Cp
2381=0.155*(15)*Cp
Cp=1024 J/kg K
Answer:
The osmotic pressure of cell is 
KPa
Explanation:
As we know the osmotic pressure is equal to
Where
i is the Van Hoff factor
c is the concentration of solution
R is the ideal gas constant
and T is the temperature.
Substituting the given values, we get -
KPa
Answer: 6.02214 × 1023 particles
Explanation: did math
I can =335ml
2cans=?
2cans×335ml÷1
= 670ml
Answer:
The thermodynamic parameter which is of significance in this case is the 'Reduction Potential' for molecular bromine which is ~ +1.1 v vs N.H.E. In other words, it is a strong oxidizing agent. The bromine will oxidize sulfur compounds in which the valence of sulfur is lower than six to sulfate.
There are many possible reactions. Here is one possible example:
Na2 S2O3 + 4Br2 + 5 H2O = 2NaHSO4 + 8 HBr
