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Elodia [21]
3 years ago
12

.Write a short paragraph describing how electronegativity and molecular shape determine the polarity of a molecule. In your para

graph, describe why chemists consider relative electronegativity values and not absolute electronegativity values when determining the polarity of a bond. Also explain how a molecule with polar bonds can be non-polar overall
Chemistry
1 answer:
Yakvenalex [24]3 years ago
3 0

Answer:

See explanation

Explanation:

Electro negativity refers to the ability of an atom in a molecule to attract the shared pair of electrons of a bond closer to itself.

In a molecule, the polarity of bonds is determined by the relative electro negativity of the bonding atoms. If the difference in electro negativity between the atoms in a bond is significant, such a bond is polar in nature e.g H-Cl, H-Br, C-F, etc.

However, the occurrence of polar bonds in a molecule alone does not guarantee the polarity of the molecule. The polarity of a molecule also depends on the shape of the molecule since dipole moment is a vector quantity.

A molecule is polar when the resultant dipole moment which is determined by the shape of the molecule is non zero.

For instance, CO2 contains two polar C-O bonds but the molecule is non polar because the two dipole moments cancel out. Also, symmetrical molecules are nonpolar irrespective of the presence of polar bonds in the molecule.

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13. Would you expect oxygen to form a cation or anion? How many electrons would it gain or lose? Why?
netineya [11]

Answer: C)Anion, it would gain 2 electrons to satisfy the octet rule.

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies and thus the electronic configuration of oxygen with 8 electrons is

O:8:1s^22s^22p^4

The cation is formed by loss of electrons and anions are formed by gain of electrons.  

In order to complete its octet and get stable, it gains 2 electrons and thus would form an anion.

O^{2-}:10:1s^22s^22p^6

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Read 2 more answers
Consider the second-order reaction:
kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after 4.53\times 10^{10} s is 0.00345 mol/L.

Explanation:

2HI(g)\rightarrow H_2(g)+I_2(g)


Rate Law: k[HI]^2


Rate constant of the reaction = k = 6.4\times 10^{-9} L/mol s

Order of the reaction = 2

Initial rate of reaction = R=1.6\times 10^{-7} Mol/L s

Initial concentration of HI =[A_o]

1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2

[A_o]=5 mol/L

Final concentration of HI after t = [A]

t = 4.53\times 10^{10} s

Integrated rate law for second order kinetics is given by:

\frac{1}{[A]}=kt+\frac{1}{[A_o]}

\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}

[A]=0.00345 mol/L

The concentration of HI after 4.53\times 10^{10} s is 0.00345 mol/L.

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