The equation in this problem is: 2Pb(NO3)2(s) --> 2PbO(s)
+ 4NO2(g) + O2(g)
And the question is what the pressure in the cylinder is
after decomposition and cooling to a temperature of 300 K.
Solution:
Moles of Pb (NO3)2 = 3.31/331 = 0.0100
2 moles of Pb (NO3)2 will decay to mold 4 moles of NO2 and 1 mole of O2. So
0.0100 moles of Pb (NO3)2 will form 0.02 moles of NO2 and 0.00500 moles of
O2
Then use the formula: PV = nRT.
P = (0.02 + 0.005) * 0.082 * 300 / 1.62
= 0.380 atm
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Answer:
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Explanation:
Step 1: Data given
Mass of sodium bicarbonate = 2.7 grams
Step 2: The balanced equation
HCl + NaHCO3 ⇔ NaCl + H2O + CO2
Step 3: Calculate moles NaHCO3
moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles
Step 4: Calculate moles HCl
For 1 mol NaHCO3 we need 1 mol HCl
For 0.032 moles NaHCO3 = 0.032 moles HCl
Step 5: Calculate mass HCl
Mass HCl = moles HCl * molar mass HCl
mass HCl = 0.032 * 36.46 g/mol= 1.17 grams
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Answer:
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced equation will be: