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sergiy2304 [10]
3 years ago
15

Write a script (Program 2) to perform t he following matrix operations. Use output commands to clearly output each problem with

a problem description and result.
(a) Create the following three matrices: A = [ 9 3 5 /2 4 2/ 6 10 5 ] B = [ 1 4 4/ 0 9 4/ 2 6 1 ] C = [ 8 15 1/ 10 8 2/ 8 5 10 ]

(b) Calculate A + B and B + A to show that addition of matrices is commutative.

(c) Calculate A +( B + C ) and ( A + B )+ C to show that addition of matrices is associative.

(d) Calculate 8( A + C ) and 8A + 8C to show that multiplication by a scalar is distributive.

(e) Calculate A( B + C ) and AB + AC to show that matrix multiplication is distributive.

(f) Does AB = BA ?

(g) Find AT (transpose of A ).

(h) Calculate B-1 (inverse of B ).

(i) Calculate the product BB-1 .

(j) Create a 2x2 matrix consisting of the lower left elements of B .

(k) Create a row vector that is the vector sum of the first row of A and the third row of C .

(l) Calculate the dot product of the second row of B and the third column of C

Engineering
1 answer:
Simora [160]3 years ago
7 0

Find the attachments for complete solution

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Answer:

i)ω=3600 rad/s

ii)V=7059.44 m/s

iii)F=1245.8 N

Explanation:

i)

We know that angular speed given as

\omega =\dfrac{d\theta}{dt}

We know that for one revolution

θ=2π

Given that time t= 2 hr

So

ω=θ/t

ω=2π/2 = π rad/hr

ω=3600 rad/s

ii)

Average speed V

V=\sqrt{\dfrac{GM}{R}}

Where M is the mass of earth.

R is the distance

G is the constant.

Now by putting the values

V=\sqrt{\dfrac{GM}{R}}

V=\sqrt{\dfrac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{8000\times 10^3}}

V=7059.44 m/s

iii)

We know that centripetal fore given as

F=\dfrac{mV^2}{R}

Here given that m= 200 kg

R= 8000 km

so now by putting the values

F=\dfrac{mV^2}{R}

F=\dfrac{200\times 7059.44^2}{8000\times 10^3}

F=1245.8 N

3 0
2 years ago
Major processing methods for fiberglass composited include which of the following? Mark all that apply) a)- Open Mold b)- Closed
Novay_Z [31]

Answer:

it is f all of the above

Explanation:

let me know if im right

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4 0
3 years ago
with a digital system, if you have measured incorrectly and use too low of a kvp for adequate penetration, what do you need to d
Lubov Fominskaja [6]

The x-ray beam's penetrating power is regulated by kVp (beam quality). Every time an exposure is conducted, the x-rays need to be powerful (enough) to sufficiently penetrate through the target area.

<h3>How does kVp impact the exposure to digital receptors?</h3>

The radiation's penetration power and exposure to the image receptor both increase as the kVp value is raised.

<h3>Exposure to the image receptor is enhanced with an increase in kVp, right?</h3>

Due to an increase in photon quantity and penetrability, exposure at the image receptor rises by a factor of five of the change in kVp, doubling the intensity at the detector with a 15% change in kVp.

To know more about kVp visit:-

brainly.com/question/17095191

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5 0
1 year ago
An amplifier with 40 dB of small-signal, open-circuit voltage gain, an input resistance of 1 MO, and an output resistance of 100
Vanyuwa [196]

convert 40db to standard gain

AL=10^40/20=100

calculate total voltage gain

=AL×RL/RL+Ri

=83.33

38.41 DB

calculate power

Pi=Vi^2/Ri Po=Vo^2/RL

power gain= Po/Pi

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3 0
3 years ago
A 4-stroke Diesel engine with a displacement of Vd = 2.5x10^-3m^3 produces a mean effective pressure of 6.4 bar at the speed of
yKpoI14uk [10]

Answer:

The power developed by engine is 167.55 KW

Explanation:

Given that

V_d=2.5\times 10^{-3} m^3

Mean effective pressure = 6.4 bar

Speed = 2000 rpm

We know that power is the work done per second.

So

P=6.4\times 100\times 2.5\times 10^{-3}\times \dfrac{2\pi \times2000}{120}

We have to notice one point that we divide by 120 instead of 60, because it is a 4 cylinder engine.

P=167.55 KW

So the power developed by engine is 167.55 KW

4 0
3 years ago
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