Answer:
I think its b lol correct me if I'm wrong
Answer:
A. 1.19 * 10^(-13) N
B. 7.12 * 10^(15) m/s²
Explanation:
Parameters given:
Speed, v = 5.05 * 10^6 m/s
Angle, A = 64°
Magnetic field strength, B = 0.160T
Mass of proton, m = 1.673 * 10^(-27) kg
Charge of proton, q = 1.6023 * 10^(-19) C
A. Magnetic force is given as:
F = q*v*B*sinA
F = 1.6023 * 10^(-19) * 5.05 * 10^6 * 0.160 * sin64
F = 1.19 * 10^(-13) N
B. Force is generally given as:
F = m*a
Hence, we can find acceleration, a, by making it the subject of formula:
a = F/m
a = (1.19 * 10^(-13))/(1.673 * 10^-27)
a = 7.12 * 10^15 m/s²
Answer:
Current in circuit = 2 amp
Explanation:
Given:
Voltage of battery = 10 V
First Resistance R1 = 1 ohm
Second Resistance R2 = 4 ohm
Resistor connected in series
Find:
Current in circuit
Computation;
Resistor connected in series
So,
Total resistance R = First Resistance R1 + Second Resistance R2
Total resistance R = 1 ohm + 4 ohm
Total resistance R = 5 ohm
Current in circuit = V / R
Current in circuit = 10 / 5
Current in circuit = 2 amp
B. Electrons are negative so one single 1 would be negative 1
Answer:
The speed it reaches the bottom is

Explanation:
Given:
, 
Using the conservation of energy theorem


, 
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Solve to w'




