Diamonds and iron, as they can't be easily put back or recreated. Remember to make sure yourself.
Hope this helps :)
Hello, sorry this is a little late!
I believe the correct answer to your question would be option D, <span>electric charges have electric fields surrounding them to allow them to exert forces on other objects without touching them.
I just took this test, and can 100% confirm this is the proper answer.
Hope this helps, and have a great day! :)</span>
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Answer:
A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.
Explanation:
The bulk modulus is represented by the following differential equation:
![K = - V\cdot \frac{dP}{dV}](https://tex.z-dn.net/?f=K%20%3D%20-%20V%5Ccdot%20%5Cfrac%7BdP%7D%7BdV%7D)
Where:
- Bulk module, measured in pascals.
- Sample volume, measured in cubic meters.
- Local pressure, measured in pascals.
Now, let suppose that bulk remains constant, so that differential equation can be reduced into a first-order linear non-homogeneous differential equation with separable variables:
![-\frac{K \,dV}{V} = dP](https://tex.z-dn.net/?f=-%5Cfrac%7BK%20%5C%2CdV%7D%7BV%7D%20%3D%20dP)
This resultant expression is solved by definite integration and algebraic handling:
![-K\int\limits^{V_{f}}_{V_{o}} {\frac{dV}{V} } = \int\limits^{P_{f}}_{P_{o}}\, dP](https://tex.z-dn.net/?f=-K%5Cint%5Climits%5E%7BV_%7Bf%7D%7D_%7BV_%7Bo%7D%7D%20%7B%5Cfrac%7BdV%7D%7BV%7D%20%7D%20%3D%20%5Cint%5Climits%5E%7BP_%7Bf%7D%7D_%7BP_%7Bo%7D%7D%5C%2C%20dP)
![-K\cdot \ln \left |\frac{V_{f}}{V_{o}} \right| = P_{f} - P_{o}](https://tex.z-dn.net/?f=-K%5Ccdot%20%5Cln%20%5Cleft%20%7C%5Cfrac%7BV_%7Bf%7D%7D%7BV_%7Bo%7D%7D%20%5Cright%7C%20%3D%20P_%7Bf%7D%20-%20P_%7Bo%7D)
![\ln \left| \frac{V_{f}}{V_{o}} \right| = \frac{P_{o}-P_{f}}{K}](https://tex.z-dn.net/?f=%5Cln%20%5Cleft%7C%20%5Cfrac%7BV_%7Bf%7D%7D%7BV_%7Bo%7D%7D%20%5Cright%7C%20%3D%20%5Cfrac%7BP_%7Bo%7D-P_%7Bf%7D%7D%7BK%7D)
![\frac{V_{f}}{V_{o}} = e^{\frac{P_{o}-P_{f}}{K} }](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7Bf%7D%7D%7BV_%7Bo%7D%7D%20%3D%20e%5E%7B%5Cfrac%7BP_%7Bo%7D-P_%7Bf%7D%7D%7BK%7D%20%7D)
The final volume is predicted by:
![V_{f} = V_{o}\cdot e^{\frac{P_{o}-P_{f}}{K} }](https://tex.z-dn.net/?f=V_%7Bf%7D%20%3D%20V_%7Bo%7D%5Ccdot%20e%5E%7B%5Cfrac%7BP_%7Bo%7D-P_%7Bf%7D%7D%7BK%7D%20%7D)
If
,
and
, then:
![V_{f} = (1\,m^{3}) \cdot e^{\frac{-10.1325\times 10^{6}\,Pa}{2.3 \times 10^{9}\,Pa} }](https://tex.z-dn.net/?f=V_%7Bf%7D%20%3D%20%281%5C%2Cm%5E%7B3%7D%29%20%5Ccdot%20e%5E%7B%5Cfrac%7B-10.1325%5Ctimes%2010%5E%7B6%7D%5C%2CPa%7D%7B2.3%20%5Ctimes%2010%5E%7B9%7D%5C%2CPa%7D%20%7D)
![V_{f} \approx 0.996\,m^{3}](https://tex.z-dn.net/?f=V_%7Bf%7D%20%5Capprox%200.996%5C%2Cm%5E%7B3%7D)
Change in volume due to increasure on pressure is:
![\Delta V = V_{o} - V_{f}](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20V_%7Bo%7D%20-%20V_%7Bf%7D)
![\Delta V = 1\,m^{3} - 0.996\,m^{3}](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%201%5C%2Cm%5E%7B3%7D%20-%200.996%5C%2Cm%5E%7B3%7D)
![\Delta V = 0.004\,m^{3}](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%200.004%5C%2Cm%5E%7B3%7D)
A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.