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34kurt
4 years ago
11

In a thunderstorm, the air must be ionized by a high voltage before a conducting path for a lightning bolt can be created. an el

ectric field of about 1.0 × 106 v/m is required to ionize dry air. what would the break- down voltage in air be if a thundercloud were 1.60 km above ground? assume that the electric field between the cloud and the ground is uniform.
Physics
1 answer:
nydimaria [60]4 years ago
4 0
We know that the electric field is equal to 1 E 6 V/m

The distance between the thundercloud and the ground is 1.6km = 1600m

Electric field = Voltage/distance

This means that the breakdown voltage must be equal to

V = 1 E 6 V/m * 1600m = 1.6 E 9 V = 1.6 GV
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Find the velocity (in m/s) of a proton that has a momentum of 4.96 X 10^-19 kg.m/s.
kramer

Answer:

The velocity of the proton is 2.965*10^{8} \frac{m}{s}

Explanation:

The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:

p=m*v Equation (1)

Where:

p: Is the momentum in kg*m/s

m: Is mass of the particle in kg

v: Is the velocity of the particle in m/s

Data known:

m= 1,6726 × 10^–27 kg : mass of the proton

p= 4.96 X 10^-19 kg.m/s.

We replace this data in the Equation (1):

4,96*10^{-19} =1.6726*10^{-27} *vv=\frac{4.9*10^{-19} }{1.6726*10^{-27} }

v=(\frac{4.96}{1.6726} )*(10^{27-19} )

v=2,965*10^{8} m/s

Answer: The velocity of the proton is 2.965*10^{8} \frac{m}{s}

3 0
3 years ago
When one side of the Earth is at high tide, then the opposite side of the Earth is also at high tide.
Rudiy27
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8 0
4 years ago
A 20.0-µF capacitor is charged by a 150.0-V power supply, then disconnected from the power and connected in series with a 0.280
natali 33 [55]

Answer

given,

Capacitance of capacitor = 20.0-µF

Voltage =  150.0-V

inductance = 0.280 m H

a) the oscillation frequency of circuit

f = \dfrac{1}{2\pi}\ sqrt{\dfrac{1}{LC}}

f = \dfrac{1}{2\pi}\ sqrt{\dfrac{1}{0.280 \times 10^{-3}\times 20 \times 10^{-6}}}

f = 2126.9 Hz

b) U = \dfrac{1}{2}CV^2

   U = \dfrac{1}{2}(20\times 10^{-6})(150)^2

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c)Current in the inductor

    V = L \dfrac{dI}{dt}

    150 = 0.28 \times 10^{-3} \dfrac{dI}{dt}

    \dfrac{dI}{dt} = 535714

instantaneous rate of change of current is equal to 535714 A/s

 

7 0
3 years ago
given that gravitational is represented by the formula f=gm1,m2/r separated by R determine the basic units of constant G​
Cloud [144]

Answer:

G is the Universal Gravitational Constant (equal to: 6.672 x 10-11Nm2/kg2).

6 0
3 years ago
A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I1 is the mo
elena55 [62]

Answer:

B: I2>I1

Explanation:

See attached file

7 0
3 years ago
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