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3 years ago

How would I graph the data in the table on the graph? WORTH 50 POINTSWILL MARK BRAINLIEST**

Physics

2 answers:

Soloha48 [4]3 years ago

5 0

Answer:

you count to the right (time) and you count up in distant and put a dot . BOOM

Explanation:

Natali5045456 [20]3 years ago

3 0

Answer:

Save the file and try to put stuff over the file. (kinda off like a picture)

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The intensity of the sound from a certain source is measured at two points along a line from the source. The points are separate

Artemon [7]

Answer:

The source is at a distance of 4.56 m from the first point.

Solution:

As per the question:

Separation distance between the points, d = 11.0 m

Sound level at the first point, L = 66.40 dB

Sound level at the second point, L'= 55.74 dB

Now,

$L = 10log_{10}\frac{I}{I_{o}}$

$I = I_{o}10^{\frac{L}{10}} = I_{o}10^{0.1L} = 10^{- 12}\times 10^{0.1\times 66.40} = 10^{- 5.36}$

$L' = 10log_{10}\frac{I'}{I_{o}}$

$I' = I_{o}10^{\frac{L'}{10}} = 10^{- 12}\times 10^{0.1\times 55.74} = 10^{- 6.426}$

where

$I_{o} = 10^{- 12} W/m^{2}$

I = Intensity of sound

Now,

$I = \frac{P}{4\pi R^{2}}$

Similarly,

$I' = \frac{P}{4\pi (R + 11.0)^{2}}$

Now,

$\frac{I}{I'} = \frac{(R + 11.0)^{2}}{R^{2}}$

$\frac{10^{- 5.36}}{10^{- 6.426}} = \frac{(R + 11.0)^{2}}{R^{2}}$

$R ^{2} + 22R + 121 = 11.64R^{2}}$

$10.64R ^{2} - 22R - 121 = 0$

Solving the above quadratic eqn, we get:

R = 4.56 m

8 0

3 years ago

NEED ANSWER FAST WILL GIVE BRAINLIEST ANSWER IF CORRECT.

Aleonysh [2.5K]

The answer would be that they are close to water hope this helps!

6 0

3 years ago

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A basketball with a mass of 1.5 kg is thrown with a force of 21 N at an angle of 60 degrees above the horizontal. What is the ve

sergey [27]

Answer:

b) 12.12 m/s² upwards

Explanation:

∑F = ma

21 sin 60° N = (1.5 kg) a

a = 12.12 m/s²

3 0

3 years ago

Which type of path do planets follow around the sun?

Elza [17]

A. ellipse...........

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3 years ago

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We often use a spoon to cool coffee by stirring. Some of the heat is conducted from the coffee to the air by this method, but th

Ilia_Sergeevich [38]

Answer:

Explanation:

heat lost by coffee = heat gain by aluminum spoon

heat lost by coffee = mc ( 85° C - T)

175 ml of water = 175 grams

175 grams = (175 / 1000) kg = 0.175 kg

heat loss by coffee = 0.175 × 4182 J/Kgk ( 85 - T) = 731.85 ( 85-T) = 62207.25 - 731.85 T

heat gain by aluminum spoon = 0.012kg × 897 J/kgK ( T - 22) = 10.764 T - 236.808

10.764 T - 236.808 = 62207.25 - 731.85 T

10.764 T + 731.85 T = 62207.25 + 236.808

T = 84.086 ° C approx 84°C

3 0

3 years ago

How would I graph the data in the table on the graph? ********WORTH 50 POINTS********WILL MARK BRAINLIEST**********

How would I graph the data in the table on the graph? WORTH 50 POINTSWILL MARK BRAINLIEST**