Answer:
Option A. 0.378M
Explanation:
Data obtained from the question include:
Molarity of acid (Ma) =..?
Volume of acid (Va) = 37.0 mL
Volume of base (Vb) = 56.0 mL
Molarity of base (Mb) = 0.250 M
Next, we shall write the balanced equation for the reaction. This is given below:
HCl + NaOH —> NaCl + H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Finally, we can determine the molarity of the acid as shown below :
MaVa/MbVb = nA/nB
Ma x 37 / 0.25 x 56 = 1
Cross multiply
Ma x 37 = 0.25 x 56
Divide both side by 37
Ma = 0.25 x 56 /37
Ma = 0.378M
Therefore, the molarity of the acid, HCl is 0.378M
Answer:
31.64...
Explanation:
The formula is volume is equal to mass over density.
So 25/0.79=31.64...
Answer:
gases
Explanation:
because the solid (steel) is the most dense, the gas (air) is the least dense, and the density of the liquid (water) is in between.
Answer:
There are 0.0186 moles of formula units in 6.35 grams of aluminum sulfate 
.
Explanation:
What's the empirical formula of aluminum sulfate?
Sulfate is an anion with a charge of -2 per ion. When sulfate ions are bonded to metals, the compound is likely ionic.
Aluminum is a group III metal. Its ions tend to carry a charge of +3 per ion.
The empirical formula of an ionic compound shall balance the charge on ions with as few ions as possible.
The least common multiple of 2 and 3 is 6. That is:
- Three sulfate ions
will give a charge of -6. - Two aluminum ions
will give a charge of +6.
Pairing three ions with two will balance the charge. Hence the empirical formula: .
What's the mass of one mole of aluminum sulfate? In other words, what's the formula mass of ?
Refer to a modern periodic table for relative atomic mass data:
- Al: 26.982;
- S: 32.06;
- O: 15.999.
There are
- two Al,
- three S, and
- twelve O
in one formula unit of .
Hence the formula mass of :
.
How many moles of formula units in 6.35 grams of ?
.
Answer:
A
Explanation:
this is because the electrons are attracted to the protons, the stronger the attraction and energy level the closer the electrons are to the nucleus. this moves them to a higher energy orbital. For example in a Bohr diagram.
