Work done = 0.5*m*[(v2)^2 - (v1)^2]
where m is mass,
v2 and v1 are the velocities.
Given that m = 1.50 x 10^3 kg, v2 = -15 m/s (decelerates), v1 = 25 kg,
Work done = 0.5 * 1.50 x 10^3 * ((-15)^2 - 25^2) = 3 x 10^5 joules
Just ignore the negative value for the final result because work is a scalar quantity.
Answer:
7.4 Ω
Explanation:
Let,
R1 = 5 Ω
R2 = 4 Ω
R3 = 6 Ω
R1 is connected series.
R2 and R3 are connected in parallel.
1 / Rp = 1 / R2 + 1 / R3
= 1 / 4 + 1 / 6
= 3 / 12 + 2 / 12
1 / Rp = 5 / 12
Rp = 12 / 5 = 2.4 Ω
Effective resistance
= R1 + Rp
= 5 + 2.4
= 7.4 Ω
Therefore, the combined resistance of 5 ohms wire arranged in series with a parallel arrangement of 4 ohms and 6 ohms wires is
7.4 Ω.
Subtract one from the to find the magnitude. Whether it's positive or negative will determine the direction.
Answer:
The magnitude of the electric field is 5.75 N/C towards positive x- axis.
Explanation:
Given that,
Point charge at origin = 2 nC
Second charge = 5 nC
Distance at x axis = 8 m
We need to calculate the electric field at the point x = 2 m
Using formula of electric field
Put the value into the formula
The direction is toward positive x- axis.
Hence, The magnitude of the electric field is 5.75 N/C towards positive x- axis.
Answer:
A. It does not exhibit projectile motion and follows a straight path down the ramp.