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3 years ago

If the thermal energy of the system increases by 600j and 1400of heat were added th the system how much work did the system do

Physics

1 answer:

Sonbull [250]3 years ago

6 0

E = Q - W
E = 1,400 - 600
E = 800

So the answer would be 800J.
Sorry for it being a week late, but for future people.

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What is the difference between a scalar and vector quantity? Give an example of each

Mkey [24]

<span>Scalar quantity: one dimensional measurement of a quantity, like temperature, or mass. Vector: more than one number associated with it. Ex: Displacement, speed, velocity.</span>

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3 years ago

In static equilibrium, the potential difference between two points inside a solid piece of metal Group of answer choices is zero

levacccp [35]

Answer:

it is zero because the electric gap is zero within the material

Explanation:

In a metal you have many free electrons, and fixed charges formed by nuclei and electrons that are not free; therefore the charge carriers are the free electrons, these have the same negative charge and due to the lectrostatic force they repel each other as far as possible without leaving the material, this implies that at two points there must be the same potential because otherwise there would be a net Caesarian force accumulating charge in a part that would be eliminated by the Coulomb force.

With this we can review the statements the strap is: it is zero because the electric gap is zero within the material

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4 years ago

Diffuse reflection occurs when the size of surface irregularities is

erik [133]

Answer:

Varies from point to point on the surface of the material.

Explanation:

Diffusion reflection is the reflection of light due to irregular reflection angles on the material surface. It might be as a result of microscopic irregularities on the material surface or just plain non reflecting ability of the material.

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3 years ago

A skier is gliding along at 4.2 m/s on horizontal, frictionless snow. He suddenly starts down a 10° incline. His speed at the bo

WARRIOR [948]

Answer:

a) 90m

b) 8.1s

Explanation:

The shortest way to finding the length of the incline is to apply an energetic analysis to determine the height of the incline. At the beginning, there is potential and kinetic energy that will turn into kinetic energy only:

$mgh+\frac{1}{2}mv_{0}^{2} =\frac{1}{2}mv_{f}^{2}$

Before we input any information, let's solve for h:

$mgh+\frac{1}{2}mv_{0}^{2} =\frac{1}{2}mv_{f}^{2}}\\\\m(gh+\frac{v_{0}^{2}}{2})=\frac{1}{2}mv_{f}^{2}}\\\\gh+\frac{v_{0}^{2}}{2}=\frac{v_{f}^{2}}{2}\\\\gh=\frac{1}{2}(v_{0}^{2}-v_{f}^{2})\\\\h=\frac{1}{2g}(v_{0}^{2}-v_{f}^{2})=\frac{1}{2*9.8\frac{m}{s^{2}}}(4.2\frac{m}{s}^{2}-18\frac{m}{s}^{2})=15.63m$

Using a sine formula we can solve for $l$ :

$Sin(10)=\frac{h}{l}\\\\l=\frac{h}{Sin(10)}=\frac{15.63m}{0.17}=90m$

In order to find the time we will use the distance formula and final velocity formula as a system of equations to solve for t:

$X=V_{0}t+\frac{at^2}{2}\\\\V_f=V_0+at$

Since the acceleration and time are both variables we will solve for acceleration in the final velocity formula and replace in the distance formula:

$V_f=V_0+at\\V_f-V_0=at\\\frac{V_f-V_0}{t}=a\\\\l=V_0t+\frac{(\frac{V_f-V_0}{t})t^2}{2}\\l=V_0t+\frac{(V_f-V_0)t}{2}\\l=t(V_0+\frac{V_f-V_0}{2})\\\\t=\frac{l}{V_0+\frac{V_f-V_0}{2}}=\frac{90m}{4.2\frac{m}{s}+\frac{18\frac{m}{s}-4.2\frac{m}{s}}{2}}=8.1s$

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3 years ago

Calculate the wavelength of the electromagentic waves with the given frequencies, and determine the type of electromagnetic radi

ololo11 [35]

To develop this problem we require the concepts related to wavelength and its expression to calculate it.

The wavelength is given by

$\lambda =\frac{c}{f}$

Where,

$c=3*10^8 m/s$ light velocity

f = frequency.

Our values are given by,

$f_1=4.38*10^{14}Hz$

$f_2= 4.14*10^{20}Hz$

$f_3 = 3.24*10^{12}Hz$

Then,

$\lambda_1=\frac{3*10^8}{4.38*10^{14}}= 6.8493*10^{-7}m$ Visible

$\lambda_2=\frac{3*10^8}{4.14*10^{20}}= 7.24*10^{-13}m$ Gamma Ray

$\lambda_3=\frac{3*10^8}{3.24*10^{12}}= 9.259*10^{-5}m$ Infrared

<em>*Note the designation on the type of rays that are, can be found in consulted via On-line or in the optical books referring to the electromagnetic spectrum table with their respective ranges.</em>

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4 years ago