There are 237. 5 g of Sulfur,S in 475 g of SO2?
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<h3>Calculation of grams of Sulfur</h3>
From the question, we can say that
- The molar mass of sulfur = 32 g/mol
- The molar mass of oxygen = 16 g/mol
Therefore,
The molar mass for SO2 = 32 + (16 × 2) g/mol = 64 g/mol
Now,
If 1 mole of SO2 contains 1 mole of S
Then 64 g of SO2, will contain 32g of S;
Such that
475 g of SO2 will give { 
} = 237. 5 g of Sulfur.
Learn more about molar mass here :brainly.com/question/18291695
Answer: 13 grams
Explanation:
The quantity of heat energy (Q) released from a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = 202.8 Joules
Mass of silver = ?
C = 0.240 J/g °C.
Φ = 65°C
Then, Q = MCΦ
202.8J = M x 0.240 J/g °C x 65°C
202.8J = M x 15.6 J/g
M = (202.8J / 15.6 J/g)
M = 13 g
Thus, the mass of silver is 13 grams
Answer:
412.1kJ
Explanation:
For the reaction , from the question -
4Fe (s) + 3O₂ (g) → 2Fe₂O₃ (s)
Δ Hrxn = Δ H°f (products) - Δ H°f (reactants)
In case the compound is in its standard state , enthalphy of formation is zero
Hence ,
for the above reaction ,
ΔHrxn =( 2 * Δ H° (Fe₂O₃ )) - [ ( 4 *Δ H° Fe ) + (3 * Δ H° O₂ )]
The value for Δ H°(Fe₂O₃ ) = - 824.2kJ/mol
Δ H° Fe = 0
Δ H° O₂ = 0
Putting in the above equation ,
ΔH rxn = ( 2 * Δ H° (Fe₂O₃ )) - 0
ΔHrxn = 2× - 824.2 kJ / mol = - 1648.4 kJ/mol
- 1648.4 kJ/mol , this much heat is released by the buring of 4 mol of Fe.
Hence ,
for 1 mol of Fe ,
- 1648.4 kJ/mol / 4 = 412.1kJ
Answer:I believe it is the Senate
Explanation:
1%. I figured it out by looking it up i dum
