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horrorfan [7]
1 year ago
10

The solubility KI is 50 g in 100 g of H2O at 20 °C. if 110 grams of ki are added to 200 grams of H2O ________

Chemistry
1 answer:
Salsk061 [2.6K]1 year ago
6 0

The solubility KI is 50 g in 100 g of H₂O at 20 °C. if 110 grams of ki are added to 200 grams of H₂O <u>the </u><u>solution </u><u>will be </u><u>saturated</u><u>.</u>

<h3>What is solubility?</h3>

Solubility is a condition where the solute is fully dissolved in the solvent. When fully mixed with the solvent.

Given that 50 g of KI is added to 100 g of water at 20 °C it means 100 g of water can dissolve a maximum of 50 g of  KCl.

1 g of water will dissolve an quantity of 0.5 g of  KCl.

To assay for 200 g of water: 200 g of water can disintegrate a maximum of (0.5) x 200 g of  KCl.

The maximum amount of KCl that will dissolve is 100 g

Actualised amount dissolved = 110 g

when Amount dissolved > Maximum solubility limit

110 g > 100 g

Thus,  the solution is saturated.

To learn more about solubility, refer to the below link:

brainly.com/question/8591226

#SPJ4

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Answer:

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Explanation:

First of all we need to calculate the heat that the water in the cooler is able to release:

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To calculate the mass of CO2 that sublimes:

-Q=\Delta H_{sub}*m

Knowing that the enthalpy of sublimation for the CO2 is: \Delta H_{sub}=571 kJ/kg

5020.8 kJ=571 kJ/kg*m

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