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iragen [17]
3 years ago
5

What is the average power output of an athlete who can life 9.0 * 10^2 kg 2.5 m in 2.0 s?

Physics
1 answer:
vampirchik [111]3 years ago
5 0

Answer:

11025 W

Explanation:

Given that athlete can lift a mass of 900 kg by 2·5 m in 2 s

<h3>Average power output is defined as the work done per unit time</h3><h3>∴ Average power output = (work done) ÷ (time taken)</h3>

Here on the object the force that acts is the weight of that object

∴ Force on that object = (mass of the object) × (acceleration due to gravity) = 900 × 9·8 = 8820 N

∴ Person requires this much force to lift that object

<h3>Work done on the object is defined as the dot product of force and displacement</h3>

∴ Work done = 8820 × 2·5 =22050 J

Power = 22050 ÷ 2 = 11025 W

∴ Average power output of the athlete = 11025 W

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<span>If there isn't any force then the normal contact force will be 


N=m*g=7.5*9.81=73.58N 

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2 years ago
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Answer:

The  angle is  \theta  =  15.48^o

Explanation:

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From projectile kinematics the time taken by the dart can be mathematically represented as

         t  =  \frac{2usin \theta }{g}

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3 years ago
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Answer:

Explanation:

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s=(30)²-(0)²/2*9.8

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